Solve for X: Balancing Inequalities in 8x < 3x + 9 and 5x + 4 < 0

Question

which value of X satisfies:

8x< 3x+9

but does not exist in:

5x+4<0

Video Solution

Step-by-Step Solution

To solve this problem, we will address each inequality separately and examine the conditions:

Step 1: Solving the First Inequality

The first inequality is 8x<3x+9 8x < 3x + 9 .

  • Subtract 3x 3x from both sides to isolate terms with x x :

8x3x<9 8x - 3x < 9

5x<9 5x < 9

  • Divide both sides by 5 to solve for x x :

x<95 x < \frac{9}{5}

Thus, the solution to the first inequality is x<1.8 x < 1.8 .

Step 2: Solving the Second Inequality

The second inequality is 5x+4<0 5x + 4 < 0 .

  • Subtract 4 from both sides:

5x<4 5x < -4

  • Divide both sides by 5:

x<45 x < -\frac{4}{5}

Thus, x<0.8 x < -0.8 .

Step 3: Analyzing the Combined Conditions

  • We need to find the values of x x that satisfy x<1.8 x < 1.8 (from Step 1) but do not satisfy x<0.8 x < -0.8 (from Step 2).
  • This indicates x x should be greater than or equal to 0.8-0.8 and still less than 1.8 1.8 .

Therefore, the solution is 0.8x<1.8 -0.8 \leq x < 1.8 .

Thus, the value of x x satisfies the desired condition, which corresponds to choice 3 in the options provided.

Therefore, the solution to the problem is 0.8x<1.8 -0.8 \leq x < 1.8 .

Answer

-0.8 ≤ x < 1.8