Solve for X: Finding the Value in (2/4 + 1/2 + 3/8 - 1/5)x = 1

Linear Equations with Multiple Fractional Terms

Solve for X:

24x+12x+38x15x=1 \frac{2}{4}x+\frac{1}{2}x+\frac{3}{8}x-\frac{1}{5}x=1

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:14 Let's solve this problem together.
00:18 First, we want to isolate the unknown variable, X.
00:24 Multiply by the common denominator to get rid of fractions.
00:34 Next, divide 40 by each fraction to simplify.
00:45 Solve each multiplication step by step.
01:05 Now, collect all the like terms together.
01:19 Finally, isolate the unknown X to find its value.
01:31 And that's how we find the solution to this question!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve for X:

24x+12x+38x15x=1 \frac{2}{4}x+\frac{1}{2}x+\frac{3}{8}x-\frac{1}{5}x=1

2

Step-by-step solution

To solve this equation, we will follow these steps:

  • Step 1: Identify the least common denominator (LCD) for the fractions 24x \frac{2}{4}x , 12x \frac{1}{2}x , 38x \frac{3}{8}x , and 15x \frac{1}{5}x .
  • Step 2: Convert each fraction to have the LCD as the denominator.
  • Step 3: Combine the fractions to form a single expression.
  • Step 4: Solve the resulting equation for x x .

Now, let's work through each step:

Step 1: The denominators are 4, 2, 8, and 5. The LCD of these numbers is 40.

Step 2: Convert each fraction:

24x=2×1040x=2040x \frac{2}{4}x = \frac{2 \times 10}{40}x = \frac{20}{40}x

12x=1×2040x=2040x \frac{1}{2}x = \frac{1 \times 20}{40}x = \frac{20}{40}x

38x=3×540x=1540x \frac{3}{8}x = \frac{3 \times 5}{40}x = \frac{15}{40}x

15x=1×840x=840x -\frac{1}{5}x = -\frac{1 \times 8}{40}x = -\frac{8}{40}x

Step 3: Combine all fractions:

2040x+2040x+1540x840x \frac{20}{40}x + \frac{20}{40}x + \frac{15}{40}x - \frac{8}{40}x

=20+20+15840x = \frac{20 + 20 + 15 - 8}{40}x

=4740x = \frac{47}{40}x

Step 4: Solve the equation 4740x=1 \frac{47}{40}x = 1 .

Multiply both sides by 4047 \frac{40}{47} to solve for x x :

x=1×4047 x = 1 \times \frac{40}{47}

x=4047 x = \frac{40}{47}

Therefore, the solution to the problem is x=4047 x = \frac{40}{47} .

3

Final Answer

4047 \frac{40}{47}

Key Points to Remember

Essential concepts to master this topic
  • LCD Strategy: Find common denominator to combine all fractional coefficients
  • Technique: Convert 24x \frac{2}{4}x to 2040x \frac{20}{40}x when LCD is 40
  • Check: Substitute x=4047 x = \frac{40}{47} back: 4740×4047=1 \frac{47}{40} \times \frac{40}{47} = 1

Common Mistakes

Avoid these frequent errors
  • Adding fractions without finding common denominator
    Don't just add 24+12+3815 \frac{2}{4} + \frac{1}{2} + \frac{3}{8} - \frac{1}{5} directly = wrong coefficient! This ignores different denominators and gives incorrect results. Always find the LCD first and convert all fractions before combining.

Practice Quiz

Test your knowledge with interactive questions

Solve for X:

\( x+3=5 \)

FAQ

Everything you need to know about this question

Why can't I just simplify each fraction first before combining?

+

You can simplify individual fractions (like 24=12 \frac{2}{4} = \frac{1}{2} ), but you still need a common denominator to add them together. The LCD method works whether fractions are simplified or not!

How do I find the LCD of 4, 2, 8, and 5?

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List multiples of the largest number (8): 8, 16, 24, 32, 40... The first multiple that all denominators divide into evenly is 40. Check: 40÷4=10, 40÷2=20, 40÷8=5, 40÷5=8 ✓

What if I get confused with all the fraction conversions?

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Take it one step at a time! Convert each fraction separately: 24=2×104×10=2040 \frac{2}{4} = \frac{2×10}{4×10} = \frac{20}{40} . Check your work by making sure the new fraction equals the original.

Can the final answer be an improper fraction?

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Yes! The answer 4047 \frac{40}{47} is proper (numerator < denominator), but improper fractions are also valid solutions. Don't convert to mixed numbers unless specifically asked.

Why multiply both sides by the reciprocal at the end?

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When you have 4740x=1 \frac{47}{40}x = 1 , multiplying both sides by 4047 \frac{40}{47} isolates x because 4740×4047=1 \frac{47}{40} × \frac{40}{47} = 1 , leaving just x x on the left side.

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