The following function is graphed below:
For which values of x is
true?
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The following function is graphed below:
For which values of x is
true?
To determine for which values of the condition holds, follow these steps:
Thus, for or .
Therefore, the solution to the problem is , corresponding to choice 2.
The following functions are graphed below:
\( f(x)=x^2-6x+8 \)
\( g(x)=4x-17 \)
For which values of x is
\( f(x)<0 \) true?
Moving everything to one side creates a standard inequality form that's easier to factor and analyze. This lets you find where the expression equals zero, which are the boundary points for your solution intervals.
After factoring, test one point from each interval in your inequality. If the test makes the inequality true, include that interval. If false, exclude it from your solution.
The graph shows where f(x) is above g(x) visually, while algebra gives the exact answer. Both should give the same result - use the graph to check your algebraic work!
The inequality uses > (greater than), not ≥. At x = 1 and x = 4, f(x) = g(x), so f(x) is not greater than g(x). Use open intervals: x < 1 or x > 4.
Look where the parabola (blue curve) is above the line (gray). This happens for x-values to the left of point C and to the right of point B, confirming x < 1 and x > 4.
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