The following function is graphed below:
For which values of x is
true?
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The following function is graphed below:
For which values of x is
true?
To solve this problem, we start by analyzing the graph of both functions. The line and a parabola intersect at points labeled and . We observe the behavior of these functions within the interval determined by these intersection points.
Therefore, the solution is within the interval , during which .
Thus, the solution to the problem is .
The following functions are graphed below:
\( f(x)=x^2-6x+8 \)
\( g(x)=4x-17 \)
For which values of x is
\( f(x)<0 \) true?
Look at the y-values on the graph! The function with the higher y-value at any given x is above the other. Between x=1 and x=4, the line g(x) is above the parabola f(x).
At intersection points, the functions are equal, not one less than the other. Since we want (strictly less than), we exclude x=1 and x=4 where .
Then the answer would be the opposite intervals! You'd have between the intersections, and outside them.
Look for points labeled on the graph or where the curves cross each other. Here, points B(4,0) and C(1,3) show where the line and parabola intersect.
For this problem, you can read directly from the graph! The visual shows clearly where one function is below the other. Just make sure to identify the correct interval notation.
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