Solve Linear Equation: Finding Perpendicular Line Through (0,0) to y-2x=2y

Which function represents a straight line that passes through the point (0,0) (0,0) and is perpendicular to the line y2x=2y y-2x=2y ?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the algebraic representation of the function
00:03 Isolate Y
00:15 This is the equation of the perpendicular function
00:22 This is the slope of the perpendicular function
00:26 The product of slopes of perpendicular lines is (-1)
00:34 Let's substitute the slope and solve to find the second slope
00:47 This is the slope of our function
00:54 A point through which our function passes according to the given data
00:57 We'll use the line equation
01:04 Let's substitute the point according to the given data
01:08 Let's substitute the slope and solve to find the intersection point (B)
01:17 This is the intersection point with the Y-axis
01:21 Now let's substitute the intersection point and slope in the line equation
01:32 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Which function represents a straight line that passes through the point (0,0) (0,0) and is perpendicular to the line y2x=2y y-2x=2y ?

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Simplify the given equation to find its slope.
  • Determine the slope for the perpendicular line using the negative reciprocal.
  • Write the equation of the line through the origin with this slope.

Let's work through each step:
Step 1: The original line is given by the equation y2x=2y y - 2x = 2y . Simplifying, we subtract y y from both sides to get 2x=y -2x = y or, equivalently, y=2x y = -2x . Here, the slope m1=2 m_1 = -2 .

Step 2: For the line to be perpendicular, its slope m2 m_2 must satisfy m1m2=1 m_1 \cdot m_2 = -1 . Thus, we have 2m2=1-2 \cdot m_2 = -1, yielding m2=12 m_2 = \frac{1}{2} .

Step 3: The equation of the line with this slope that passes through the origin is of the form y=mx y = mx . Substituting the slope 12 \frac{1}{2} , we have y=12x y = \frac{1}{2}x .

Therefore, the function representing the straight line through the origin and perpendicular to the given line is y=12x y = \frac{1}{2}x , which corresponds to choice 1.

3

Final Answer

y=12x y=\frac{1}{2}x

Practice Quiz

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Look at the function shown in the figure.

When is the function positive?

xy-4-7

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