The number of respondents to a survey is .
of them and another responded that they do not like pistachio ice cream, while the remaining 8 participants said that they really liked the flavor.
How many participants were there in the survey?
We have hundreds of course questions with personalized recommendations + Account 100% premium
The number of respondents to a survey is .
of them and another responded that they do not like pistachio ice cream, while the remaining 8 participants said that they really liked the flavor.
How many participants were there in the survey?
To solve this problem, we'll follow these steps:
Step 1: Set up the equation:
Step 2: Simplify the equation:
First, calculate :
Insert this back into the equation:
Multiply the entire equation by 3 to eliminate the fractions:
Simplify:
Reorganize the equation:
Solve for :
Step 3: Calculate the total number of participants:
Substitute into :
Therefore, the total number of participants is 84.
84
Solve for X:
\( 3x=18 \)
The key is identifying the total. Here, the total survey size is , and all respondents must add up to this total: those who don't like it plus those who do like it.
Multiplying by 3 clears the fraction and makes the equation easier to solve. Remember to multiply every single term on both sides by 3!
Double-check your algebra steps! Common errors include forgetting to distribute the properly or making arithmetic mistakes when combining like terms.
Check that all groups add up: 56 people don't like it (2/3 of 84 = 56), 20 more don't like it (2x = 20), and 8 like it. Total: 56 + 20 + 8 = 84 ✓
The problem says of all respondents and another 2x don't like pistachio. So it's 2/3 of the entire survey size , not just part of it.
Get unlimited access to all 18 Linear Equations (One Variable) questions, detailed video solutions, and personalized progress tracking.
Unlimited Video Solutions
Step-by-step explanations for every problem
Progress Analytics
Track your mastery across all topics
Ad-Free Learning
Focus on math without distractions
No credit card required • Cancel anytime