Solve Linear Relationships: Finding x When 8x-14 < 5x+4

Daniel has a number of sweets.

Mariano has 5 times plus 4 more sweets than Daniel

Iván has 8 times plus 14 fewer sweets than Daniel.

Iván has fewer sweets than Mariano.

What is the possible number of sweets that Daniel has in terms of x?

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1

Understand the problem

Daniel has a number of sweets.

Mariano has 5 times plus 4 more sweets than Daniel

Iván has 8 times plus 14 fewer sweets than Daniel.

Iván has fewer sweets than Mariano.

What is the possible number of sweets that Daniel has in terms of x?

2

Step-by-step solution

To solve this problem, we'll contemplate the mathematical relationships between the sweets.

  • Step 1: Expression Setup
    Mariano's sweets can be expressed as 5x+4 5x + 4 , and Iván's sweets are 8x14 8x - 14 .
  • Step 2: Inequality Setup
    Given that Iván has fewer sweets, establish an inequality: 8x14<5x+4 8x - 14 < 5x + 4 .
  • Step 3: Solve the Inequality
    Simplify the inequality:
    8x14<5x+4 8x - 14 < 5x + 4
    Subtract 5x 5x from both sides:
    3x14<4 3x - 14 < 4
    Add 14 to both sides:
    3x<18 3x < 18
    Divide by 3:
    x<6 x < 6
  • Step 4: Considering Logical Constraints
    Since sweets represent physical goods, x x must be positive. Therefore, x>0 x > 0 .
  • Step 5: Conclusion
    Combining these inequalities, 0<x<6 0 < x < 6 .

Therefore, the possible number of sweets that Daniel has is 0<x<6 0 < x < 6 .

3

Final Answer

0<x<6 0 < x < 6

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Solve the inequality:


\( 5-3x>-10 \)

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