Solve Mixed Numbers: 13⅓ minus 7¼ Subtraction Problem

To solve the problem of subtracting $+7\frac{1}{4}$ from $+13\frac{1}{3}$, we follow these steps:

• Convert $13\frac{1}{3}$ to an improper fraction:

$13\frac{1}{3} = \frac{39}{3} + \frac{1}{3} = \frac{39 + 1}{3} = \frac{40}{3}$

• Convert $7\frac{1}{4}$ to an improper fraction:

$7\frac{1}{4} = \frac{28}{4} + \frac{1}{4} = \frac{28 + 1}{4} = \frac{29}{4}$

• Find a common denominator for $\frac{40}{3}$ and $\frac{29}{4}$. The least common multiple of 3 and 4 is 12.
• Convert $\frac{40}{3}$ to a fraction with a denominator of 12:

$\frac{40}{3} \times \frac{4}{4} = \frac{160}{12}$

• Convert $\frac{29}{4}$ to a fraction with a denominator of 12:

$\frac{29}{4} \times \frac{3}{3} = \frac{87}{12}$

• Subtract the fractions:

$\frac{160}{12} - \frac{87}{12} = \frac{160 - 87}{12} = \frac{73}{12}$

• Convert $\frac{73}{12}$ back to a mixed fraction:

$73 \div 12 = 6$ remainder $1$, so it equals $6\frac{1}{12}$.

Therefore, the solution to the problem is $6\frac{1}{12}$.