Solve Multi-digit Subtraction: 6002 minus 373

$\begin{aligned} &6002 \\ -& \\ &~~373 \\ &\underline{\phantom{776}} & \\ \end{aligned}$

Let's solve $6002 - 373$ using the vertical subtraction method:

• Step 1: Write the numbers in column form, ensuring they are aligned by place value: $\begin{array}{c} 6002 \\ -~~373 \\ \hline \end{array}$

• Step 2: Subtract each digit starting from the right (units place). First, inspect the units place:

  • We need to subtract 3 from 2. Since 3 > 2, we must borrow.

  • Borrow 1 from 600 (next higher order, thousands in this case):

    • The result: Change 6002 to 5992.

  • Now, subtract $12 - 3 = 9$, in the units place.

  $\begin{array}{c} 5992 \\ -~~373~~~ \\ \hline ~~~~~~9 \\ \end{array}$

• Step 3: Move to the tens place:

  • Subtract $9 - 7 = 2$.

  $\begin{array}{c} 5992 \\ -~~373~~~ \\ \hline ~~~29 \\ \end{array}$

• Step 4: Move to the hundreds place:

  • Subtract $9 - 3 = 6$.

  $\begin{array}{c} 5992 \\ -~~373~~~~ \\ \hline ~629 \\ \end{array}$

• Step 5: Move to the thousands place:

  • We have 5 remaining and no subtraction needed here.

  • Therefore, the result is $5629$.

  $\begin{array}{c} 5992 \\ -~~373~~~ \\ \hline 5629 \\ \end{array}$

Therefore, the solution to $6002 - 373$ is $5629$.