00:06 Let's solve this problem together.
00:09 Imagine we have a number A under a root with order B, then under another root with order C.
00:15 This equals number A, under one root with order B times C. Pretty neat, right?
00:22 Alright, let's use this formula in our exercise.
00:28 First, we need to multiply the orders.
00:35 Now, let's break down 512. It's two to the power of nine.
00:40 Remember, if we have a number A to the power of B with root order B squared…
00:46 The root and power cancel out, leaving us with just A.
00:50 Let's apply this in our exercise and see it work.
00:53 And there you have it! That's the solution. Great job!