Solve: Subtracting Positive Fractions 1/8 - 4/6 Step by Step

To solve the problem $(+\frac{1}{8})-(+\frac{4}{6})$, let's follow these steps:

• Step 1: Simplify the fraction $\frac{4}{6}$ to its simplest form. Since both the numerator and the denominator are divisible by 2, we have $\frac{4}{6} = \frac{2}{3}$.
• Step 2: Find the least common denominator (LCD) for the fractions $\frac{1}{8}$ and $\frac{2}{3}$. The denominators are 8 and 3, so the LCD is 24.
• Step 3: Convert both fractions to have the denominator of 24.
• For $\frac{1}{8}$, multiply both the numerator and the denominator by 3 to get: $\frac{1 \times 3}{8 \times 3} = \frac{3}{24}$.
• For $\frac{2}{3}$, multiply both the numerator and the denominator by 8 to get: $\frac{2 \times 8}{3 \times 8} = \frac{16}{24}$.
• Step 4: Subtract the numerators over the common denominator: $\frac{3}{24} - \frac{16}{24} = \frac{3 - 16}{24} = \frac{-13}{24}$.
• Step 5: The fraction $\frac{-13}{24}$ is already in its simplest form since 13 is a prime number and does not divide 24.

Therefore, the solution to the problem is $-\frac{13}{24}$.

From the given multiple-choice options, the correct choice is option 2:

$-\frac{13}{24}$