Solve the Complex Inequality: |-5 + |2b - 3| + |-b + 4| < 0

Absolute Value Inequalities with No Solution

Given:

5+2b3+b+4<0 |-5 + |2b - 3| + |-b + 4| < 0

Which of the following statements is necessarily true?

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Step-by-step written solution

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1

Understand the problem

Given:

5+2b3+b+4<0 |-5 + |2b - 3| + |-b + 4| < 0

Which of the following statements is necessarily true?

2

Step-by-step solution

The given inequality is: 5+2b3+b+4<0 |-5 + |2b - 3| + |-b + 4| < 0 .

This translates to checking if the sum of absolute values and other constants can yield a negative result.

Let's consider the expression inside the absolute values:

5+2b3+b+40 |-5 + |2b - 3| + |-b + 4| \ge 0 for all real numbers b b .

The absolute value of any expression is always non-negative. Therefore, 2b30|2b - 3| \ge 0 and b+40|-b + 4| \ge 0 .

Adding these non-negative values to -5 will still yield a result that is greater than or equal to -5. Since -5 is not less than 0, the inequality cannot hold true for any real number b b .

Hence, the statement "No solution" is correct.

3

Final Answer

No solution

Key Points to Remember

Essential concepts to master this topic
  • Properties: Absolute values are always non-negative or zero
  • Analysis: 2b30 |2b - 3| \geq 0 and b+40 |-b + 4| \geq 0 for all b
  • Check: If minimum value ≥ 0, then expression < 0 is impossible ✓

Common Mistakes

Avoid these frequent errors
  • Ignoring the outer absolute value bars
    Don't solve |-5 + |2b - 3| + |-b + 4|| by just looking at inner expressions = missing the key insight! The outer absolute value makes the entire expression non-negative. Always recognize that |anything| ≥ 0, so |anything| < 0 has no solutions.

Practice Quiz

Test your knowledge with interactive questions

Given:

\( \left|2x-1\right|>-10 \)

Which of the following statements is necessarily true?

FAQ

Everything you need to know about this question

Why can't an absolute value be negative?

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By definition, absolute value measures distance, and distance is never negative. So x0 |x| \geq 0 for any real number x.

What if the expression inside gets really negative?

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It doesn't matter! Even if 5+2b3+b+4 -5 + |2b - 3| + |-b + 4| equals -10, the absolute value of -10 is still +10, which is positive.

How do I recognize a no solution inequality?

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Look for patterns like |expression| < 0. Since absolute values are never negative, these inequalities are always impossible.

Could there be a special value of b that works?

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No! The minimum value of 5+2b3+b+4 |-5 + |2b - 3| + |-b + 4|| is 0, which occurs when the inside expression equals 0. Since 0 is not less than 0, no value of b works.

What's the difference between no solution and all real numbers?

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No solution means the inequality is never true. All real numbers means it's always true. This problem has no solution because absolute values can't be negative.

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