Solve the Fraction Sum: 4/12 + 1/3 + 1/6 Step-by-Step

To solve the problem, we start by finding the least common denominator (LCD) for the fractions $\frac{4}{12}$, $\frac{1}{3}$, and $\frac{1}{6}$.

The denominators are 12, 3, and 6. We need to find the smallest number that is a multiple of each of these numbers. The LCD of 12, 3, and 6 is 12.

Next, we convert each fraction to have this common denominator:

• $\frac{4}{12}$ already has 12 as the denominator.
• $\frac{1}{3}$ can be converted to have 12 as the denominator by multiplying both the numerator and the denominator by 4: $\frac{1}{3} = \frac{1 \times 4}{3 \times 4} = \frac{4}{12}$.
• $\frac{1}{6}$ can be converted to have 12 as the denominator by multiplying both the numerator and the denominator by 2: $\frac{1}{6} = \frac{1 \times 2}{6 \times 2} = \frac{2}{12}$.

Now, we simply add these fractions:

$\frac{4}{12} + \frac{4}{12} + \frac{2}{12} = \frac{4 + 4 + 2}{12} = \frac{10}{12}$.

Therefore, the solution to the problem is $\frac{10}{12}$.