Solve the Inequality |2x-1| > -10: Key Insights

Absolute Value Inequalities with Negative Constants

Given:

2x1>10 \left|2x-1\right|>-10

Which of the following statements is necessarily true?

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1

Understand the problem

Given:

2x1>10 \left|2x-1\right|>-10

Which of the following statements is necessarily true?

2

Step-by-step solution

Let's solve the problem:
Step 1: Recognize that the inequality we are dealing with is 2x1>10 \left|2x-1\right| > -10 .
Step 2: Consider the nature of absolute values: for any real xx, 2x1\left|2x-1\right| is always non-negative (i.e., 0\geq 0).
Step 3: Observe that the right side of the inequality, 10-10, is negative. Therefore, the inequality 2x1>10\left|2x-1\right| > -10 is always true because 2x1\left|2x-1\right| as a non-negative quantity will always be greater than any negative number.
Step 4: Since the inequality condition always holds true, this means that the statement is valid for all xx.

Therefore, the correct answer is that the inequality holds for all xx.

The solution to the problem is For all x.

3

Final Answer

For all x

Key Points to Remember

Essential concepts to master this topic
  • Property: Absolute values are always non-negative for any real number
  • Technique: Compare |expression| ≥ 0 with negative right side like -10
  • Check: Test any value: |2(0)-1| = 1 > -10 ✓

Common Mistakes

Avoid these frequent errors
  • Solving absolute value inequalities with standard algebraic methods
    Don't try to split 2x1>10 |2x-1| > -10 into two cases like positive inequalities = wasted time and confusion! When the right side is negative, the inequality is automatically true since absolute values can't be negative. Always recognize that any absolute value is greater than any negative number.

Practice Quiz

Test your knowledge with interactive questions

Given:

\( \left|2x-1\right|>-10 \)

Which of the following statements is necessarily true?

FAQ

Everything you need to know about this question

Why doesn't this inequality need to be solved step by step?

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Because absolute values are always non-negative! Since 2x10 |2x-1| \geq 0 for any real number, it's automatically greater than any negative number like -10.

What if the right side was positive instead of negative?

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Then you'd need to solve it properly! For example, 2x1>10 |2x-1| > 10 would require splitting into two cases: 2x-1 > 10 OR 2x-1 < -10.

How can I quickly recognize when an absolute value inequality has all real numbers as solutions?

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Look at the right side! If it's negative and the inequality is > or ≥, then the solution is all real numbers. Absolute values can never be negative!

Could an absolute value inequality ever have no solution?

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Yes! If you have expression<negativenumber |expression| < negative number , there would be no solution because absolute values can't be less than negative numbers.

What's the difference between |2x-1| > -10 and |2x-1| < -10?

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  • 2x1>10 |2x-1| > -10 : All real numbers (always true)
  • 2x1<10 |2x-1| < -10 : No solution (never true)

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