Solve the inequality:
7x+c≤4x−2 7x+c \leq 4x-2 7x+c≤4x−2
To solve the inequality7x+c≤4x−2 7x+c \leq 4x-2 7x+c≤4x−2, we follow these steps:
Subtract 4x 4x 4x from both sides: 3x+c≤−2 3x + c \leq -2 3x+c≤−2
Subtract c c c from both sides: 3x≤−2−c 3x \leq -2 - c 3x≤−2−c
Divide both sides by 3 3 3: x≤−c+23 x \leq -\frac{c+2}{3} x≤−3c+2
x≤−c+23 x \leq -\frac{c+2}{3} x≤−3c+2