Solve the Linear System: Find Solutions for x/2 + y = 3, x + 2y = 6

x2+y=3 \frac{x}{2}+y=3

x+2y=6 x+2y=6

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Step-by-step video solution

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00:00 Solve
00:03 Let's multiply one of the equations by 2, so we can subtract between them
00:11 Now let's subtract between the equations
00:14 Let's simplify what we can
00:20 There are infinite solutions
00:27 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

x2+y=3 \frac{x}{2}+y=3

x+2y=6 x+2y=6

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Express one equation in terms of a single variable.
  • Step 2: Substitute into the other equation.
  • Step 3: Evaluate and determine the solution type.

Now, let's work through each step:
Step 1: Solve the first equation for xx:
x2+y=3x=62y\frac{x}{2} + y = 3 \quad \Rightarrow \quad x = 6 - 2y.

Step 2: Substitute x=62yx = 6 - 2y into the second equation:
x+2y=6(62y)+2y=6x + 2y = 6 \quad \Rightarrow \quad (6 - 2y) + 2y = 6.

Step 3: Simplifying equation:
62y+2y=66=66 - 2y + 2y = 6 \quad \Rightarrow \quad 6 = 6.

This equation 6=66 = 6 is always true, indicating that both equations are dependent and represent the same line.

Therefore, the system has infinite solutions.

3

Final Answer

Infinite solutions

Practice Quiz

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\( \begin{cases} x+y=8 \\ x-y=6 \end{cases} \)

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