x3+y1=4
x5−y1=4
We begin by examining the given system of equations:
x3+y1=4 --- (1)
x5−y1=4 --- (2)
Let's eliminate y1 by adding equations (1) and (2):
(x3+y1)+(x5−y1)=4+4
x3+x5=8
x8=8
Solving for x, we have:
x=1
Now, substitute x=1 back into equation (1):
13+y1=4
3+y1=4
y1=1
Solving for y, we obtain:
y=1
Thus, the solution to the system of equations is x=1 and y=1.
The correct answer choice is: x=1,y=1.