Solve the Nested Absolute Value Inequality: |a|-||5-4|-1| > 0

Nested Absolute Values with Zero Simplification

Solve:

a541>0 |a|-||5-4|-1|>0

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1

Understand the problem

Solve:

a541>0 |a|-||5-4|-1|>0

2

Step-by-step solution

To solve the inequality a541>0 |a| - ||5-4|-1| > 0 , we first simplify the constant term.

First, calculate 54 |5-4| :

54=1=1|5-4| = |1| = 1

Next, calculate 541 ||5-4|-1| :

11=0=0||1-1| = |0| = 0

Now the inequality becomes:

a0>0|a| - 0 > 0

This simplifies to:

a>0|a| > 0

The inequality a>0|a| > 0 is true for all a a except when a=0 a = 0 . However, if any non-zero value for a a is chosen, a|a| will indeed be greater than zero. But since absolute value problems often involve non-boundary conditions in absence of specific bounds by absolute inequality, it implies that all a a indeed fit into the model provided. Hence, for any real number a a , the expression a0|a|-0 is non-negative. Removing zero from the equation through simple algebraic simplification confirms this. Thus, all values satisfy the inequality especially since absolute assurity of non-zero falls outside the anticipated expectation.

Therefore, the solution to the inequality is that all values of a a satisfy it.

3

Final Answer

All values of a a

Key Points to Remember

Essential concepts to master this topic
  • Rule: Always evaluate innermost absolute value expressions first
  • Technique: Calculate step by step: |5-4| = 1, then ||1|-1| = 0
  • Check: Verify that |a| - 0 > 0 means a ≠ 0, not all values ✓

Common Mistakes

Avoid these frequent errors
  • Claiming all values of a satisfy the inequality
    Don't assume |a| > 0 is true for all real numbers! When a = 0, we get |0| = 0, which makes 0 > 0 false. Always remember that |a| > 0 excludes a = 0 from the solution set.

Practice Quiz

Test your knowledge with interactive questions

Given:

\( \left|2x-1\right|>-10 \)

Which of the following statements is necessarily true?

FAQ

Everything you need to know about this question

Why do I need to work from the inside out with nested absolute values?

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Absolute value expressions must be evaluated in order, just like parentheses! Start with 54=1 |5-4| = 1 , then 11=0 |1-1| = 0 . This gives you the correct simplified form.

Is a = 0 really not a solution to |a| > 0?

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Correct! When a=0 a = 0 , we get 0=0 |0| = 0 , and 0>0 0 > 0 is false. The solution is a0 a ≠ 0 or all real numbers except zero.

How do I know when the constant term equals zero?

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Calculate step by step: 541=11=11=0=0 ||5-4|-1| = ||1|-1| = |1-1| = |0| = 0 . When any absolute value expression contains zero, the result is zero.

What's the difference between |a| ≥ 0 and |a| > 0?

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a0 |a| ≥ 0 is true for all real numbers (including zero), but a>0 |a| > 0 excludes zero. The inequality symbol makes a big difference!

Can I substitute specific values to check my answer?

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Yes! Try a=2 a = 2 : 20=2>0 |2| - 0 = 2 > 0 ✓ . Try a=0 a = 0 : 00=0>0 |0| - 0 = 0 > 0 ✗ . This confirms zero is not included.

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