Solve the Quadratic Equation 2x² - 8 = 0: Finding the Roots

Question

Solve the following equation:

2x28=0 2x^2-8=0

Video Solution

Solution Steps

00:00 Find X
00:03 Isolate X
00:21 Extract the root
00:27 When extracting a root there are always 2 solutions (positive, negative)
00:33 And this is the solution to the question

Step-by-Step Solution

To solve the quadratic equation 2x28=0 2x^2 - 8 = 0 , we will follow these steps:

  • Step 1: Isolate x2 x^2 .
  • Step 2: Solve for x x by taking square roots.

Let's perform each step:

Step 1: Isolate x2 x^2
Start with the given equation:
2x28=0 2x^2 - 8 = 0

Add 8 to both sides to isolate the term involving x x :
2x2=8 2x^2 = 8

Divide both sides by 2 to solve for x2 x^2 :
x2=4 x^2 = 4

Step 2: Solve for x x by taking square roots
Take the square root of both sides, remembering to consider both the positive and negative roots:
x=±4 x = \pm \sqrt{4}

Simplify the square root:
x=±2 x = \pm 2

This means there are two solutions:
x1=2 x_1 = 2 and x2=2 x_2 = -2

Therefore, the solutions to the equation 2x28=0 2x^2 - 8 = 0 are x1=2,x2=2 x_1 = -2, x_2 = 2 .

Matching this with the choices provided, the correct answer is choice 3: x1=2,x2=2 x_1 = -2, x_2 = 2 .

Answer

x1=2,x2=2 x_1=-2,x_2=2