Solve the Quadratic Equation: x² - 25 = 0 Step by Step

Quadratic Equations with Perfect Square Forms

Solve the following equation

x225=0 x^2-25=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 Isolate X
00:11 Extract root
00:16 When extracting a root there are always 2 solutions (positive, negative)
00:21 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following equation

x225=0 x^2-25=0

2

Step-by-step solution

To solve the equation x225=0 x^2 - 25 = 0 , follow these steps:

  • Step 1: Isolate the square term: Begin by rewriting the equation to isolate x2 x^2 :

x225=0 x^2 - 25 = 0
Add 25 25 to both sides to obtain:
x2=25 x^2 = 25

  • Step 2: Extract the square roots: To solve x2=25 x^2 = 25 , take the square root of both sides. Remember to consider both the positive and negative roots:

x=±25 x = \pm \sqrt{25}

  • Step 3: Simplify: Calculate the square root of 25:

25=5 \sqrt{25} = 5

Therefore, the solutions are:
x=5 x = 5
and
x=5 x = -5

Thus, the solutions to the equation x225=0 x^2 - 25 = 0 are x1=5 x_1 = 5 and x2=5 x_2 = -5 .

Verifying with the provided choices, the correct choice matches the solution x1=5,x2=5 x_1 = 5, x_2 = -5 .

Therefore, the solution to the problem is x1=5,x2=5 x_1 = 5, x_2 = -5 .

3

Final Answer

x1=5,x2=5 x_1=5,x_2=-5

Key Points to Remember

Essential concepts to master this topic
  • Rule: Move constant to right side before taking square roots
  • Technique: From x2=25 x^2 = 25 , get x=±5 x = ±5
  • Check: Substitute both solutions: 5225=0 5^2 - 25 = 0 and (5)225=0 (-5)^2 - 25 = 0

Common Mistakes

Avoid these frequent errors
  • Forgetting the negative square root
    Don't just write x = 5 when solving x2=25 x^2 = 25 = missing half the solution! Every positive number has two square roots. Always write x=±25 x = ±\sqrt{25} to get both x = 5 and x = -5.

Practice Quiz

Test your knowledge with interactive questions

Solve the following equation:


\( 2x^2-8=x^2+4 \)

FAQ

Everything you need to know about this question

Why are there two solutions to this equation?

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Because when you square both 5 and -5, you get 25! Think about it: 52=25 5^2 = 25 and (5)2=25 (-5)^2 = 25 . So both values make the original equation true.

Can I use factoring instead of square roots?

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Yes! You can factor x225=0 x^2 - 25 = 0 as (x5)(x+5)=0 (x-5)(x+5) = 0 . This gives the same solutions: x = 5 and x = -5.

What if the number under the square root isn't a perfect square?

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You'd leave it in radical form! For example, if x2=7 x^2 = 7 , then x=±7 x = ±\sqrt{7} . You don't need to calculate the decimal unless specifically asked.

How do I know this is a quadratic equation?

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Look for the highest power of x! Since we have x2 x^2 (x to the second power), this is a quadratic equation. The standard form is ax2+bx+c=0 ax^2 + bx + c = 0 .

Why do we write the answer as x₁ = 5, x₂ = -5?

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The subscripts help us distinguish between the two solutions. In math, we often label multiple answers this way. You could also write the solution set as {5,5} \{-5, 5\} .

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