Solve the Quadratic Equation: -6x² + 12x - 14 = 0

Quadratic Equations with Negative Discriminants

Solve the following equation:

6x2+12x14=0 -6x^2+12x-14=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 Pay attention to coefficients
00:10 Use the roots formula
00:27 Substitute appropriate values according to the given data and solve for X
00:48 Calculate the products and square
01:05 There's no such thing as a root of a negative number, therefore there's no solution
01:10 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following equation:

6x2+12x14=0 -6x^2+12x-14=0

2

Step-by-step solution

To solve the quadratic equation 6x2+12x14=0-6x^2 + 12x - 14 = 0, we'll use the quadratic formula:

The quadratic formula is x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.

Let's calculate step by step:

  • Identify the coefficients: Here, a=6a = -6, b=12b = 12, and c=14c = -14.
  • Compute the discriminant: b24ac=1224(6)(14)=144336=192b^2 - 4ac = 12^2 - 4(-6)(-14) = 144 - 336 = -192.
  • Assess the discriminant: The discriminant is 192-192, which is less than zero.
  • Since the discriminant is negative, there are no real solutions to the equation.

Therefore, the correct answer to the problem is "No solution."

3

Final Answer

No solution

Key Points to Remember

Essential concepts to master this topic
  • Discriminant Rule: When b24ac<0 b^2 - 4ac < 0 , no real solutions exist
  • Formula: b24ac=144336=192 b^2 - 4ac = 144 - 336 = -192 indicates no real roots
  • Check: Negative discriminant always means no real solutions ✓

Common Mistakes

Avoid these frequent errors
  • Ignoring the negative discriminant and continuing calculations
    Don't keep applying the quadratic formula when the discriminant is negative = impossible square root of negative number! This leads to confusion with imaginary numbers. Always check the discriminant first and conclude 'no real solutions' when it's negative.

Practice Quiz

Test your knowledge with interactive questions

a = Coefficient of x²

b = Coefficient of x

c = Coefficient of the independent number


what is the value of \( a \) in the equation

\( y=3x-10+5x^2 \)

FAQ

Everything you need to know about this question

What does it mean when there are no real solutions?

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It means the parabola doesn't cross the x-axis at any point! Since this equation has a=6<0 a = -6 < 0 , the parabola opens downward but stays entirely below the x-axis.

Why can't I take the square root of -192?

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In real numbers, we can't take square roots of negative values. The square root of -192 would involve imaginary numbers, which are beyond basic algebra.

How do I know the discriminant is negative before calculating?

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Always calculate b24ac b^2 - 4ac step by step: 1224(6)(14)=144336 12^2 - 4(-6)(-14) = 144 - 336 . The key is being careful with negative signs!

Could I have solved this by factoring instead?

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You could try, but since there are no real solutions, the quadratic won't factor using real numbers. The quadratic formula with discriminant checking is the most reliable method.

What if I made a sign error in my discriminant calculation?

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Double-check each step: b2=144 b^2 = 144 , 4ac=4(6)(14)=336 4ac = 4(-6)(-14) = 336 , so 144336=192 144 - 336 = -192 . Sign errors are common with negative coefficients!

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