Solve the following equation:
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Solve the following equation:
To solve the inequality , we first factor the quadratic expression as .
Note that for all real numbers because it is a square. Furthermore, equals zero only when .
This means that the expression never actually becomes negative for any real . The vertex of the parabola, a perfect square, simply touches the x-axis at but does not dip below.
Therefore, there is no solution to the inequality over the real numbers.
The conclusion is that there is no negative domain.
There is no negative domain.
Solve the following equation:
\( x^2+4>0 \)
Because is a perfect square, and squares of real numbers are always zero or positive. Since we need it to be less than zero, there's no real number that works!
It means the parabola never goes below the x-axis. In this case, just touches the x-axis at x = 3 but stays above or on it everywhere else.
Look for these clues: perfect square trinomials like are never negative, and upward-opening parabolas that touch but don't cross the x-axis.
Yes! If the inequality were , then all real numbers except x = 3 would be solutions. The direction of the inequality matters!
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