Solve the following equation:
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Solve the following equation:
To solve this problem, let's examine the inequality .
The expression consists of two terms: and . Notice that:
Combining these observations, we see that:
Thus, there are no values of for which the expression is zero or negative. Instead, the expression is always positive for all real numbers .
Therefore, the solution to the inequality is all values of .
All values of
Solve the following equation:
\( x^2+4>0 \)
Because means , but squares of real numbers cannot be negative! This equation has no real solutions, so there are no boundary points to consider.
Look for expressions like . Since always, adding a positive constant makes the entire expression always positive.
Then you would solve to find boundary points x = ±2, then test intervals. The key difference is subtracting vs. adding the constant!
Not necessary here! Since is always positive, the graph of y = x² + 4 is always above the x-axis. The solution is simply all real numbers.
Test several values: when x = 0, we get 4 > 0 ✓. When x = -3, we get 9 + 4 = 13 > 0 ✓. When x = 100, we get 10,004 > 0 ✓. Every test confirms the pattern!
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