Solve the Quadratic: Unravel the Equation 5x² + 1.5x + 1 = 0

Question

Solve the following equation:

5x2+112x+1=0 5x^2+1\frac{1}{2}x+1=0

Video Solution

Solution Steps

00:08 Let's find the value of X.
00:12 First, we need to identify the coefficients. Pause and look at the equation. Ready?
00:28 Now, we'll use the roots formula. Take it step by step and follow along.
00:49 Let's substitute the appropriate values given in the problem, and solve it together.
01:14 Next, we calculate the square and the products. Let's do it slowly.
01:36 Remember, you can't have a root of a negative number in this case.
01:40 Therefore, there is no solution to this problem. And that's okay!

Step-by-Step Solution

Let's solve the quadratic equation 5x2+1.5x+1=0 5x^2 + 1.5x + 1 = 0 using the quadratic formula.

Step 1: Identify the coefficients for the equation ax2+bx+c=0 ax^2 + bx + c = 0 :
a=5 a = 5
b=1.5 b = 1.5
c=1 c = 1

Step 2: Calculate the discriminant Δ=b24ac \Delta = b^2 - 4ac .
Δ=(1.5)2451=2.2520=17.75\Delta = (1.5)^2 - 4 \cdot 5 \cdot 1 = 2.25 - 20 = -17.75

Step 3: Analyze the discriminant:
Since the discriminant Δ=17.75\Delta = -17.75 is negative, this indicates that there are no real solutions to the equation 5x2+1.5x+1=0 5x^2 + 1.5x + 1 = 0 .

Therefore, the equation has no solution in the real number system.

Answer

No solution