Solve the System: 2x + y = 10 and x - y = 2 Step-by-Step

{2x+y=10xy=2 \begin{cases} 2x + y = 10 \\ x-y=2 \end{cases}

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1

Understand the problem

{2x+y=10xy=2 \begin{cases} 2x + y = 10 \\ x-y=2 \end{cases}

2

Step-by-step solution

To solve the system of equations:

2x+y=10 2x + y = 10

xy=2 x - y = 2

First, solve the second equation for x x :

x=y+2 x = y + 2

Substitute x=y+2 x = y + 2 into the first equation:

2(y+2)+y=10 2(y + 2) + y = 10

Expand and simplify:

2y+4+y=10 2y + 4 + y = 10

3y+4=10 3y + 4 = 10

Subtract 4 from both sides:

3y=6 3y = 6

Divide by 3:

y=2 y = 2

Substitute y=2 y = 2 back into x=y+2 x = y + 2 :

x=2+2=4 x = 2 + 2 = 4

Thus, the solution is:

x=4,y=2 x = 4, y = 2

3

Final Answer

x=4,y=2 x = 4, y = 2

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\( \begin{cases} 2x + y = 10 \\ x-y=2 \end{cases} \)

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