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To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Add the units digits of both numbers:
. Here, 7 is placed in the units place, and 1 is carried over to the tens column.
Step 2: Add the tens digits along with the carry-over:
. Here, 0 is placed in the tens place, and 1 is carried over to the hundreds column.
Step 3: Add the hundreds digits along with the carry-over:
. Here, 0 is placed in the hundreds place, and 1 is carried over to the thousands column.
The final sum is , where 1 is now the digit in the thousands place.
Therefore, the solution to the problem is .
1007
\( \begin{aligned} &12 \\ +& \\ &~~2 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When adding digits in a column gives you 10 or more, you write the units digit in that column and carry the tens digit to the next column on the left. For example: 8 + 9 = 17, so write 7 and carry 1.
We start from the units column because any carrying affects the next column to the left. If we started from the left, we'd miss the carried amounts from the right columns!
That's completely normal! In this problem, we carried from units to tens and from tens to hundreds. Just handle each carry one column at a time as you work left.
You can check by adding in reverse: . If you get back to your original first number, your addition is correct!
When hundreds carrying happens (like ), you create a new thousands place. Write 0 in hundreds and 1 in the new thousands column, giving you a 4-digit answer.
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