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Let's solve the problem by completing an addition of the numbers vertically.
Write the numbers vertically, aligning them by their place values:
\begin{array}{c@{}c@{}c@{}c@{}c}
& 1 & 5 & 4 & 7 \\
+ & & 7 & 6 & 5 & 6 \\
\end{array}
Add the digits starting from the rightmost (units place):
Units Place: . Write 3 and carry over 1 to the tens place.
Tens Place: , plus 1 from the carry-over equals 10. Write 0 and carry over 1 to the hundreds place.
Hundreds Place: , plus 1 from the carry-over equals 12. Write 2 and carry over 1 to the thousands place.
Thousands Place: , plus 1 from the carry-over equals 9. Write 9.
The final addition gives us:
Thus, the sum of 1547 and 7656 is .
9203
\( \begin{aligned} &83 \\ +& \\ &~~6 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When two digits add up to 10 or more, you write the ones digit in that column and carry the tens digit to the next column left. For example: means write 3, carry 1.
We start from the units place (rightmost) because any carrying affects the column to the left. If we started from the left, we'd have to go back and fix our work when we carry!
Your final answer will be wrong! Always remember to add the carried digit to your next column. It helps to write small carry numbers above each column as reminders.
Try adding the numbers in a different order, or use subtraction to check: . If you get back one of your original numbers, your addition is correct!
No problem! Just imagine invisible zeros in front of the shorter number. For example, treat 1547 as 01547 when adding to 7656, so all columns line up properly.
The column method is actually the most reliable way for multi-digit addition! While mental math tricks exist, showing your work step-by-step prevents errors and helps you learn the place value system.
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