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To solve this problem, we'll perform vertical addition:
Calculating step-by-step:
Step 1: Add the units digit.
- Add (units place of 236) and (units place): .
- This requires regrouping since the sum is more than . Thus, write in the units place and carry over to the tens place.
Step 2: Add the tens digit.
- Add the carry-over to the tens digit of 236, : .
- Place in the tens column.
Step 3: Add the hundreds digit. - There is only the hundreds digit from 236, and no carry-over: Thus result is also in the hundreds column.
Putting it all together, the sum is: .
Therefore, the solution to the problem is .
243
\( \begin{aligned} &90 \\ +& \\ &~~9\\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When two digits add up to 10 or more, you can't write a two-digit number in one place! The becomes 3 in the units and 1 carried to tens.
Regrouping means taking 10 ones and trading them for 1 ten (or 10 tens for 1 hundred). It's like exchanging 10 pennies for 1 dime!
Always write the carry-over above the next column to the left. For , write the 1 above the tens column.
You still add the carry-over! In this problem, there's no tens digit in 7, so you add in the tens column.
Yes! Try subtraction: . If you get back to your original number, your addition is correct!
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