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To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Consider the ones digits. For 872 and 9, the ones digits are 2 and 9.
Adding these gives us .
Step 2: In base-10 addition, if the sum of digits in a place (in this case, the ones place) exceeds 9, we carry over to the next leftward digit. Thus, we write 1 in the ones place and carry over 1 to the tens place.
Step 3: Now, we add the tens digits. For the tens, we have 7 (from 872) and the 1 from our carry over.
Thus, .
Step 4: After adding the tens digits, check if there's any carry over. Since 8 is not greater than 9, no further carrying is needed.
Step 5: Finally, add the hundreds place digits. For the hundreds, we have 8 (from 872), and there was no carry from the tens, giving .
Combining these sum results, we have the final sum as:
Hundreds: 8
Tens: 8
Ones: 1
Therefore, the sum of 872 and 9 is .
Therefore, the solution to the problem is .
The choice that corresponds to this solution is Choice 4: .
881
\( \begin{aligned} &83 \\ +& \\ &~~6 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
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