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To solve this problem, we'll follow these steps:
Now, let's perform the addition:
Vertical addition setup:
Step 1: Add the ones digits: . We write 1 in the ones place and carry over 1 to the tens place.
Step 2: Add the tens digits (3 from 33 and 0 from 8, since it has no tens digit), including any carry: .
This gives us:
Therefore, the solution to the problem is .
41
\( \begin{aligned} &90 \\ +& \\ &~~9\\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When two digits add up to 10 or more, you write the ones digit in your answer and 'carry' the tens digit to the next column. For example, means write 1 and carry 1.
Each column can only hold one digit! Writing 11 would mean you have 11 ones, but 10 ones actually equals 1 ten. That's why we carry the extra ten to the tens column.
Treat missing digits as zero! In this problem, 8 has no tens digit, so we think of it as 08. Then add: .
Try adding the numbers horizontally (left to right): . If you get the same answer both ways, you're correct!
Yes, always! Start with the ones place (rightmost column) and work left. This ensures you handle any carrying correctly from smaller to larger place values.
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