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To solve this problem, we'll follow these steps:
Therefore, the solution to the problem is .
70
\( \begin{aligned} &90 \\ +& \\ &~~9\\ &\underline{\phantom{776}} & \\ \end{aligned} \)
Each column can only hold one digit! When you get 10, the 0 stays in the ones place and the 1 moves to the tens place. This is called carrying or regrouping.
That's okay! Just treat it as zero. In this problem, 3 is the same as 03, so you're adding 6 + 0 + 1 (the carried amount) = 7 in the tens column.
You carry whenever the sum of digits in any column is 10 or greater. Write down the ones digit and carry the tens digit to the next column on the left.
Yes! Try subtraction: 70 - 3 should equal 67. Or add the numbers in a different order: 3 + 67 = 70. Both methods confirm your answer is correct!
No problem! Just work column by column from right to left. Each time you get 10 or more, write the ones digit and carry the rest to the next column. Keep going until you finish all columns.
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