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To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Align numbers:
Step 2: Begin with the units place:
8 (units from 378) + 5 (units from 455) = 13.
Write down 3 in the units place, and carry over 1 to the tens place.
Step 3: Move to the tens place:
7 (tens from 378) + 5 (tens from 455) + 1 (carried over) = 13.
Write down 3 in the tens place, and carry over 1 to the hundreds place.
Step 4: Finally, add the hundreds place:
3 (hundreds from 378) + 4 (hundreds from 455) + 1 (carried over) = 8.
Write down 8 in the hundreds place.
The final sum is, therefore:
Therefore, the solution to the problem is .
833
\( \begin{aligned} &12 \\ +& \\ &~~2 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When adding digits gives you 10 or more, you write down the units digit and carry the tens digit to the next column. For example: 8+5=13, so write 3 and carry 1.
We start from the units place because any carrying affects the next column to the left. If we started from the left, we'd have to keep changing our answers!
Your answer will be too small! In this problem, forgetting the carried 1 in the tens place would give you 723 instead of 833. Always double-check you've added all carried numbers.
Try these methods:
No problem! Just align them by place value on the right side. You can imagine invisible zeros in the empty places. The addition process stays exactly the same.
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