We have hundreds of course questions with personalized recommendations + Account 100% premium
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Align the numbers.
48
+52
___
Step 2: Add the digits in the units column:
8 (from 48) + 2 (from 52) = 10.
This gives us 0 in the units place and we carry over 1 to the tens place.
Step 3: Add the digits in the tens column, including the carried over 1:
4 (from 48) + 5 (from 52) + 1 (carryover) = 10.
Thus, the digit 0 goes to the tens place, and 1 will be placed in the hundreds place.
Therefore, the full solution looks like this:
48
+52
___
100
Therefore, the solution to the problem is .
100
\( \begin{aligned} &90 \\ +& \\ &~~9\\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When two digits add up to 10 or more, you write down the units digit and 'carry' the tens digit to the next column. For example, 8 + 2 = 10, so write 0 and carry the 1 to the tens place.
Place value alignment is crucial! The units digits must line up under units, and tens digits under tens. This ensures you're adding the correct place values together.
Always start with the rightmost column (units place) and work your way left. This is because any carryover from the units affects the tens column, and so on.
Try adding the numbers horizontally: 48 + 52. You can also break it down: 40 + 50 = 90 and 8 + 2 = 10, so 90 + 10 = 100.
Handle each column one at a time, from right to left. Each carryover only affects the next column to the left, so take your time and work systematically.
Get unlimited access to all 18 Arithmetic Operations questions, detailed video solutions, and personalized progress tracking.
Unlimited Video Solutions
Step-by-step explanations for every problem
Progress Analytics
Track your mastery across all topics
Ad-Free Learning
Focus on math without distractions
No credit card required • Cancel anytime