Solve (x+1)(x-3)(x+7)(-7)=0: Finding All Solutions Using Zero Product Property

Zero Product Property with Constant Factor

Solve the following equation:

(x+1)(x3)(x+7)(7)=0 (x+1)(x-3)(x+7)(-7)=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:10 Let's solve this problem!
00:13 Remember, any number times zero equals zero!
00:19 Now, we'll check when each factor in this multiplication equals zero.
00:35 Let's find the unknown variable.
00:41 Great! That's one solution.
00:45 Next, we'll use the same method for the second factor.
00:54 Awesome! Here's a second solution.
00:58 Finally, let's apply the method to the third factor.
01:06 Fantastic! This is the third solution. All three together solve the question.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following equation:

(x+1)(x3)(x+7)(7)=0 (x+1)(x-3)(x+7)(-7)=0

2

Step-by-step solution

Let's solve the following equation:

7(x+1)(x3)(x+7)=0 -7(x+1)(x-3)(x+7)=0

First, let's divide both sides of the equation by the number outside of the parentheses:

7(x+1)(x3)(x+7)=0/:(7)(x+1)(x3)(x+7)=0 -7(x+1)(x-3)(x+7)=0 \hspace{6pt}\text{/}:(-7)\\ (x+1)(x-3)(x+7)=0

Remember that the product of an expression equals 0 only if at least one of the multiplying expressions equals zero,

Therefore we should obtain three simple equations and solve them by isolating the variable in each one:

x+1=0x=1 x+1=0\\ \boxed{x=-1} or:

x3=0x=3 x-3=0\\ \boxed{x=3} or:

x+7=0x=7 x+7=0\\ \boxed{x=-7} Hence the solution to the equation is:

x=1,37 \boxed{x=-1,3-7} The correct answer is answer D.

3

Final Answer

1,3,7,7 -1,3,-7,7

Key Points to Remember

Essential concepts to master this topic
  • Zero Product Rule: When product of factors equals zero, at least one factor must equal zero
  • Technique: Divide by constant first: 7(x+1)(x3)(x+7)=0÷(7) -7(x+1)(x-3)(x+7)=0 ÷ (-7)
  • Check: Substitute each solution: (1+1)(13)(1+7)(7)=0 (-1+1)(-1-3)(-1+7)(-7) = 0

Common Mistakes

Avoid these frequent errors
  • Including the constant factor as a solution
    Don't set the constant -7 equal to zero and write x = -7 as a solution! Constants are always non-zero, so they don't create solutions. Always divide by constants first to isolate the variable factors.

Practice Quiz

Test your knowledge with interactive questions

\( x^2+6x+9=0 \)

What is the value of X?

FAQ

Everything you need to know about this question

Why do we divide by -7 first instead of setting each factor to zero?

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The constant -7 cannot equal zero, so it doesn't give us any solutions! We divide by -7 to simplify and focus on the factors that contain variables: (x+1)(x3)(x+7) (x+1)(x-3)(x+7) .

What if the constant factor was positive instead of negative?

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It doesn't matter! Whether the constant is positive or negative, we still divide both sides by it. The zero product property only applies to variable expressions.

How do I know which factors contain variables?

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Look for factors with x in them: (x+1),(x3),(x+7) (x+1), (x-3), (x+7) have variables, but (7) (-7) is just a number. Only set the variable factors equal to zero!

Can I solve this without dividing by -7 first?

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Yes, but it's harder! You'd get the same three solutions from the variable factors, but keeping the 7 -7 makes the work messier. Always simplify first when possible.

Why does the final answer list x = -7 when we said constants don't create solutions?

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Look carefully! The solution x=7 x = -7 comes from solving x+7=0 x + 7 = 0 , not from the constant factor (7) (-7) . These are different!

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