Solve x² + 4 > 0: Quadratic Inequality Practice

The inequality we are solving is $x^2 + 4 > 0$. Let's analyze this expression:

Consider $x^2$, which is always non-negative for any real number $x$. Therefore, $x^2 \geq 0$.

When we add 4 to $x^2$, the result is $x^2 + 4$. Because $x^2 \geq 0$, adding 4 ensures that $x^2 + 4$ is always greater than 4.

Thus, for any real value of $x$, the expression $x^2 + 4$ will always satisfy the inequality $x^2 + 4 > 0$.

In conclusion, the inequality holds true for all values of $x$. So, the answer is: All values of $x$.