00:00 Solve
00:03 Each time we consider a shortage of 2 digits, and then we'll place
00:06 Subtract ones from ones, and place in ones
00:09 6 is less than 8
00:13 In this case, we borrow a hundred from the hundreds place, for the tens
00:17 Which will turn the hundreds from 0 to 3
00:21 And now we'll have 16 instead of 6, in tens!
00:26 Subtract tens from tens, and place in tens
00:31 Subtract hundreds from hundreds, and place in hundreds
00:36 5 is less than 6
00:40 Therefore we borrow ten thousand from the ten thousands place, for the thousands
00:44 Which will turn the ten thousands from 7 to 6
00:47 And now we'll have 15 instead of 5, in thousands!
00:51 Subtract thousands from thousands, and place in thousands
00:57 6 is less than 8
01:00 Therefore we borrow from the hundred thousands place, for the ten thousands
01:05 Which will turn the hundred thousands from 2 to 1
01:09 And now we'll have 16 instead of 6, in ten thousands!
01:12 Subtract ten thousands from ten thousands, and place
01:16 Subtract hundred thousands from hundred thousands, and place
01:20 And this is the solution to the problem