AD = BC
AD || BC
According to which theorem are the triangles ΔADB≅ΔCBD congruent?
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AD = BC
AD || BC
According to which theorem are the triangles ΔADB≅ΔCBD congruent?
We are given: AD=BC
The angle ADB is equal to the angle CBD since AD is parallel to BC and the corresponding angles are equal between parallel lines.
DB=DB since it is a common side.
Therefore, we have two triangles that are congruent according to the S.A.S. (side, angle, side) theorem.
According to the S.A.S. theorem
Look at the triangles in the diagram.
Which of the statements is true?
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