Triangle Height Problem: Finding Perpendicular Distance of 24 Units

Triangle Proportionality with Similar Segments

AAABBBCCCDDDEEEFFFJJJ2461.5 Choose the correct answer.

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Choose the correct answer
00:03 The triangles share the same vertex angle (z)
00:07 Equal angles according to given data (z)
00:12 Similar triangles according to A.A.
00:17 Find the similarity ratio
00:28 Put appropriate values according to the given data and solve to find the ratio
00:34 This is the similarity ratio between the triangles
00:41 The triangles share the same vertex angle (z)
00:48 Equal angles according to given data (z)
00:53 Similar triangles according to A.A
01:03 Find the similarity ratio
01:13 Put appropriate values according to the given data and solve to find the ratio
01:17 This is the similarity ratio between the triangles
01:25 Because the similarity ratio is equal, we'll use the transition rule
01:29 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

AAABBBCCCDDDEEEFFFJJJ2461.5 Choose the correct answer.

2

Step-by-step solution

To solve this problem, let's follow these steps:

  • Step 1: Identify similar triangles and related segments.
  • Step 2: Apply proportions based on geometric similarity principles.
  • Step 3: Compare with the given options.

Let's work through each step:

Step 1: From the geometry, consider triangles and line segments such as ADAD, AFAF, and ABAB. These segments often form part of similar triangles with known properties.

Step 2: Based on triangle similarity properties, the ratio for segments in similar figures should follow a coherent pattern like that of proportions described for viable geometric figures, namely: ADAF=AFAB \frac{AD}{AF} = \frac{AF}{AB} This indicates the relationship of subsegments generated by these points. Use triangle proportionality theorem or similar property for derivation.

Step 3: Match this with the answer selections provided. The choice: ADAF=AFAB \frac{AD}{AF} = \frac{AF}{AB} corresponds directly with option 3 among the provided choices.

Therefore, the correct answer is: ADAF=AFAB \frac{AD}{AF}=\frac{AF}{AB} .

3

Final Answer

ADAF=AFAB \frac{AD}{AF}=\frac{AF}{AB}

Key Points to Remember

Essential concepts to master this topic
  • Similar Triangles: Equal ratios exist between corresponding sides of similar triangles
  • Technique: Use geometric mean property ADAF=AFAB \frac{AD}{AF} = \frac{AF}{AB} for segments
  • Check: Verify proportions cross-multiply to equal products: AD × AB = AF² ✓

Common Mistakes

Avoid these frequent errors
  • Confusing corresponding segments in proportions
    Don't randomly match segments without identifying the similar triangles first = wrong ratios! This leads to incorrect proportions that don't reflect the actual geometric relationships. Always identify which triangles are similar and match corresponding parts systematically.

Practice Quiz

Test your knowledge with interactive questions

If it is known that both triangles are equilateral, are they therefore similar?

FAQ

Everything you need to know about this question

How do I identify which segments correspond to each other?

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Look for similar triangles first! When you have altitude lines like DE and JF drawn to the hypotenuse, they create smaller triangles that are similar to the original and to each other.

Why is the geometric mean important in this problem?

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The geometric mean relationship ADAF=AFAB \frac{AD}{AF} = \frac{AF}{AB} appears when an altitude is drawn to the hypotenuse of a right triangle. AF becomes the geometric mean of AD and AB.

What makes this different from regular proportion problems?

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This involves geometric relationships in triangles, not just numerical ratios. The segments are related through similarity and altitude properties, creating specific proportion patterns.

How can I remember which proportion is correct?

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Focus on the pattern: when you have segments on a line created by perpendiculars, the middle segment is often the geometric mean of the outer segments. So AF is between AD and AB.

What if I can't see the similar triangles clearly?

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Look for right angles created by the perpendicular lines (shown as small squares). These create similar triangles that share the same angles, making their sides proportional.

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