Is equality correct?
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Is equality correct?
To solve this problem, we'll perform the distribution as follows:
Distribute the term across .
Calculate and .
Calculate and .
Let's compute these multiplications:
Let us expand the left side using distribution:
=
= .
After simplification, the expression becomes:
.
Comparing this with the right-hand side of the original equation , we observe that both sides are equal.
Therefore, the two sides of the equation are equal, confirming that the given equality is correct.
The final solution is Yes.
Yes
\( (3+20)\times(12+4)= \)
The distributive property requires each term in the first binomial to be multiplied by each term in the second binomial. Missing any combination gives an incomplete result!
No! equals . You can rearrange terms in any order since addition is commutative.
First terms, Outer terms, Inner terms, Last terms. For : First: , Outer: , Inner: , Last:
Take it step by step! Remember: negative times negative equals positive , but negative times positive equals negative .
Yes! Substitute simple values like into both sides. If gives the same result, you're correct!
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