Sequences / Skips up to a million: Jumps of 100

Examples with solutions for Sequences / Skips up to a million: Jumps of 100

Exercise #1

Complete the sequence:

653,150, 653,250,  653{,}150,\ 653{,}250, \ \ldots

Step-by-Step Solution

To solve the problem, we identify the sequence pattern:

  • Determine the difference between the given terms: 653,250653,150=100 653,250 - 653,150 = 100 .
  • Since the difference between consecutive terms is 100, this indicates the rule of the sequence.
  • To find the next terms, continue adding 100 to the last known term:
    • Next term after 653,250: 653,250+100=653,350 653,250 + 100 = 653,350 .
    • Next term after 653,350: 653,350+100=653,450 653,350 + 100 = 653,450 .
    • Next term after 653,450: 653,450+100=653,550 653,450 + 100 = 653,550 .

Thus, the completed sequence is 653,150,653,250,653,350,653,450,653,550 653,150, 653,250, 653,350, 653,450, 653,550 .

Therefore, the next three numbers in the sequence are 653,350,653,450,653,550 653{,}350, 653{,}450, 653{,}550 .

Answer

653,350, 653,450, 653,550 653{,}350,\ 653{,}450,\ 653{,}550

Exercise #2

Complete the sequence:

900,900, 900,800,  900{,}900,\ 900{,}800, \ \ldots

Step-by-Step Solution

To find the pattern in the sequence 900,900,900,800,900,900, 900,800, \ldots, we need to determine the difference between successive terms.

Step 1: Calculate the difference between the first two terms:

900,800900,900=100900,800 - 900,900 = -100

Step 2: The sequence decreases by 100. Using this consistent decrease, we can determine the next terms:

  • From 900,800900,800, subtract 100: 900,800100=900,700900,800 - 100 = 900,700
  • From 900,700900,700, subtract 100: 900,700100=900,600900,700 - 100 = 900,600
  • From 900,600900,600, subtract 100: 900,600100=900,500900,600 - 100 = 900,500

Therefore, the completed sequence is 900,700,900,600,900,500900,700, 900,600, 900,500.

Answer

900,700, 900,600, 900,500 900{,}700,\ 900{,}600, \ 900{,}500