Sequences / Skips up to a million: Jumps of 10,000

To solve this problem, we'll determine the pattern in the sequence and extend it:

• Step 1: Identify the pattern in the sequence
• Step 2: Calculate the common difference
• Step 3: Use the common difference to extend the sequence

Now, let's work through each step:
Step 1: The sequence starts with $380{,}000$ and $370{,}000$. By observation, the numbers are decreasing.
Step 2: Calculate the common difference: $370{,}000 - 380{,}000 = -10{,}000$. This tells us the sequence decreases by $10{,}000$ for each step.
Step 3: Continue the sequence using the common difference:

• The next term after $370{,}000$ is $370{,}000 - 10{,}000 = 360{,}000$.
• The following term is $360{,}000 - 10{,}000 = 350{,}000$.
• The term after that is $350{,}000 - 10{,}000 = 340{,}000$.

Therefore, the completed sequence is: $360{,}000,\ 350{,}000, \ 340{,}000$.

To solve this sequence problem, we'll follow these steps:

• Step 1: Identify the difference between the given terms.
• Step 2: Use this difference to calculate subsequent terms.

Now, let's proceed with these steps:
Step 1: The given terms are 200,000 and 210,000. The difference between these terms is $210,000 - 200,000 = 10,000$.

Step 2: Assuming this sequence follows an arithmetic pattern, the common difference is $10,000$. Therefore, each subsequent number is the previous number plus $10,000$.

Let's find the next few terms:

• The term after 210,000 is $210,000 + 10,000 = 220,000$.
• The subsequent term is $220,000 + 10,000 = 230,000$.
• The next term is $230,000 + 10,000 = 240,000$.

Therefore, the complete sequence is $200,000, 210,000, 220,000, 230,000, 240,000$.

The correct answer choice is: $220,000, 230,000, 240,000$, which matches option 3.