Extended Distributive Property Practice Problems & Worksheets

Master the extended distributive property with step-by-step practice problems. Learn to multiply two binomials, simplify expressions, and solve real-world applications.

πŸ“šWhat You'll Master in This Practice Session
  • Multiply two binomials using the extended distributive property method
  • Apply FOIL technique to expressions like (x+3)(x-2) with confidence
  • Combine like terms after distributing to simplify final answers
  • Solve real-world area problems using binomial multiplication
  • Handle negative signs correctly when multiplying binomial expressions
  • Work with variables and coefficients in extended distributive problems

Understanding Extended Distributive Property

Complete explanation with examples

The extended distributive property allows us to solve exercises with two sets of parentheses that are multiplied by eachother.

For example: (a+1)Γ—(b+2) (a+1)\times(b+2)

To find the solution, we will go through the following steps:

  • Step 1: Multiply the first term in the first parentheses by each of the terms in the second parentheses.
  • Step 2: Multiply the second term in the first parentheses by each of the terms in the second parentheses.
  • Step 3: Associate like terms.

ab+2a+b+2 ab+2a+b+2

The Extended Distributive Property

Detailed explanation

Practice Extended Distributive Property

Test your knowledge with 28 quizzes

Solve the exercise:

\( (5x-2)(3+x)= \)

Examples with solutions for Extended Distributive Property

Step-by-step solutions included
Exercise #1

Solve the following problem:

(xβˆ’6)(x+8)= (x-6)(x+8)=

Step-by-Step Solution

In order to simplify the given expression, open the parentheses using the extended distribution law:

(a+b)(c+d)=ac+ad+bc+bd (\textcolor{red}{a}+\textcolor{blue}{b})(c+d)=\textcolor{red}{a}c+\textcolor{red}{a}d+\textcolor{blue}{b}c+\textcolor{blue}{b}d

Note that in the formula template for the above distribution law, it is a given that the operation between the terms inside of the parentheses is addition. Furthermore the sign preceding the term is of great significance and must be taken into consideration;

Proceed to apply the above formula to the expression to open out the parentheses.

(xβˆ’6)(x+8)↓(x+(βˆ’6))(x+8) (x-6)(x+8)\\ \downarrow\\ \big(\textcolor{red}{x}+\textcolor{blue}{(-6)}\big)(x+8)\\ Let's begin then with opening the parentheses:

(x+(βˆ’6))(x+8)xβ‹…x+xβ‹…8+(βˆ’6)β‹…x+(βˆ’6)β‹…8x2+8xβˆ’6xβˆ’48 \big(\textcolor{red}{x}+\textcolor{blue}{(-6)}\big)(x+8)\\ \textcolor{red}{x}\cdot x+\textcolor{red}{x}\cdot8+\textcolor{blue}{(-6)}\cdot x+\textcolor{blue}{(-6)}\cdot8\\ x^2+8x-6x-48

To calculate the above multiplications operations we used the multiplication table as well as the laws of exponents for multiplication between terms with identical bases:

amβ‹…an=am+n a^m\cdot a^n=a^{m+n}

In the next step we'll combine like terms which we define as terms where the variable (or variables ), in this case x, have identical exponents . (Note that in the absence of one of the variables from the expression, we'll consider its exponent as zero power due to the fact that raising any number to the zero power yields the result 1) Apply the commutative property of addition and proceed to arrange the expression from highest to lowest power from left to right (Note: treat the free number as having zero power):
x2+8xβˆ’6xβˆ’48x2+2xβˆ’48 \textcolor{purple}{x^2}\textcolor{green}{+8x-6x}\textcolor{orange}{-48}\\ \textcolor{purple}{x^2}\textcolor{green}{+2x}\textcolor{orange}{-48}\\ When combining like terms as shown above, we highlighted the different terms using colors, as well as treating the sign preceding the term as an inseparable part of it.

The correct answer is answer A.

Answer:

x2+2xβˆ’48 x^2+2x-48

Video Solution
Exercise #2

Solve the following problem:

(x+2)(xβˆ’4)= (x+2)(x-4)=

Step-by-Step Solution

In order to solve the given problem, we will use the FOIL method. FOIL stands for First, Outer, Inner, Last. This helps us to systematically expand the product of the two binomials:

  • Step 1: Multiply the First terms.

The first terms of each binomial are x x and x x . Multiply these together to obtain xΓ—x=x2 x \times x = x^2 .

  • Step 2: Multiply the Outer terms.

The outer terms are x x and βˆ’4-4. Multiply these. together to obtain xΓ—βˆ’4=βˆ’4x x \times -4 = -4x .

  • Step 3: Multiply the Inner terms.

The inner terms are 2 2 and x x . Multiply these together to obtain 2Γ—x=2x 2 \times x = 2x .

  • Step 4: Multiply the Last terms.

The last terms are 2 2 and βˆ’4-4. Multiply these together to obtain 2Γ—βˆ’4=βˆ’8 2 \times -4 = -8 .

Proceed to combine all these results together:

x2βˆ’4x+2xβˆ’8 x^2 - 4x + 2x - 8

Finally, combine like terms:

Combine βˆ’4x-4x and 2x2x to obtain βˆ’2x-2x.

The expanded form of the expression is therefore:

x2βˆ’2xβˆ’8 x^2 - 2x - 8

Thus, the solution to the problem is x2βˆ’2xβˆ’8 x^2 - 2x - 8 , which corresponds to choice 1.

Answer:

x2βˆ’2xβˆ’8 x^2-2x-8

Video Solution
Exercise #3

(xβˆ’6)(x+2)= (x-6)(x+2)=

Step-by-Step Solution

To solve this problem, we need to multiply the binomials (xβˆ’6) (x-6) and (x+2) (x+2) using the distributive property (FOIL method):

  • First: Multiply the first terms: xβ‹…x=x2 x \cdot x = x^2
  • Outer: Multiply the outer terms: xβ‹…2=2x x \cdot 2 = 2x
  • Inner: Multiply the inner terms: βˆ’6β‹…x=βˆ’6x -6 \cdot x = -6x
  • Last: Multiply the last terms: βˆ’6β‹…2=βˆ’12 -6 \cdot 2 = -12

Now, we have the terms: x2 x^2 , 2x 2x , βˆ’6x -6x , and βˆ’12 -12 .
We combine the linear terms:

x2+2xβˆ’6xβˆ’12=x2βˆ’4xβˆ’12 x^2 + 2x - 6x - 12 = x^2 - 4x - 12

This is the expanded form of the quadratic expression in standard form.
Therefore, the solution to the problem is x2βˆ’4xβˆ’12 x^2 - 4x - 12 .

Answer:

x2βˆ’4xβˆ’12 x^2-4x-12

Video Solution
Exercise #4

(x+y)(xβˆ’y)= (x+y)(x-y)=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the structure of the expression
  • Step 2: Apply the difference of squares formula
  • Step 3: Simplify the expression

Now, let's work through each step:
Step 1: The expression is (x+y)(xβˆ’y)(x+y)(x-y), which resembles the difference of squares. Step 2: Using the formula for the difference of squares, (a+b)(aβˆ’b)=a2βˆ’b2(a+b)(a-b) = a^2 - b^2, we set a=xa = x and b=yb = y. Step 3: Applying the formula, we have:

(x+y)(xβˆ’y)=x2βˆ’y2(x+y)(x-y) = x^2 - y^2.

Therefore, the solution to the problem is x2βˆ’y2 x^2-y^2 .

Answer:

x2βˆ’y2 x^2-y^2

Video Solution
Exercise #5

(3+20)Γ—(12+4)= (3+20)\times(12+4)=

Step-by-Step Solution

Simplify this expression paying attention to the order of arithmetic operations. Exponentiation precedes multiplication whilst division precedes addition and subtraction. Parentheses precede all of the above.

Therefore, let's first start by simplifying the expressions within the parentheses. Then we can proceed to perform the multiplication between them:

(3+20)β‹…(12+4)=23β‹…16=368 (3+20)\cdot(12+4)=\\ 23\cdot16=\\ 368

Therefore, the correct answer is option A.

Answer:

368

Video Solution

Frequently Asked Questions

What is the extended distributive property formula?

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The extended distributive property formula is (a+b)(c+d) = ac + ad + bc + bd. You multiply each term in the first parentheses by each term in the second parentheses, then combine like terms if possible.

How do you multiply two binomials step by step?

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Follow these steps: 1) Multiply the first term in the first binomial by each term in the second binomial, 2) Multiply the second term in the first binomial by each term in the second binomial, 3) Combine like terms to simplify your final answer.

What's the difference between basic and extended distributive property?

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Basic distributive property involves one term multiplied by a binomial: a(b+c) = ab + ac. Extended distributive property involves multiplying two binomials: (a+b)(c+d) = ac + ad + bc + bd.

How do you handle negative signs in extended distributive property?

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Treat negative signs as part of the terms. Remember that multiplying two negatives gives a positive result, while multiplying a positive and negative gives a negative result. For example: (-3)(-5) = +15, but (-3)(+5) = -15.

What are common mistakes when using extended distributive property?

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Common mistakes include: β€’ Forgetting to multiply all four combinations of terms β€’ Making sign errors with negative numbers β€’ Failing to combine like terms in the final answer β€’ Rushing through the multiplication without checking work

When do you use the extended distributive property in real life?

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The extended distributive property is used in calculating areas of rectangles with variable dimensions, solving quadratic equations, and simplifying algebraic expressions in physics and engineering problems.

Is FOIL the same as extended distributive property?

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Yes, FOIL (First, Outer, Inner, Last) is a memory device for the extended distributive property when multiplying two binomials. Both methods produce the same result by ensuring you multiply all combinations of terms.

How do you check if your extended distributive property answer is correct?

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You can check by: 1) Substituting simple numbers for variables and verifying both sides equal the same value, 2) Expanding your answer back to factored form, or 3) Using online algebra calculators to verify your work.

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