Extended Distributive Property Practice Problems & Worksheets

Master the extended distributive property with step-by-step practice problems. Learn to multiply two binomials, simplify expressions, and solve real-world applications.

πŸ“šWhat You'll Master in This Practice Session
  • Multiply two binomials using the extended distributive property method
  • Apply FOIL technique to expressions like (x+3)(x-2) with confidence
  • Combine like terms after distributing to simplify final answers
  • Solve real-world area problems using binomial multiplication
  • Handle negative signs correctly when multiplying binomial expressions
  • Work with variables and coefficients in extended distributive problems

Understanding Extended Distributive Property

Complete explanation with examples

The extended distributive property allows us to solve exercises with two sets of parentheses that are multiplied by eachother.

For example: (a+1)Γ—(b+2) (a+1)\times(b+2)

To find the solution, we will go through the following steps:

  • Step 1: Multiply the first term in the first parentheses by each of the terms in the second parentheses.
  • Step 2: Multiply the second term in the first parentheses by each of the terms in the second parentheses.
  • Step 3: Associate like terms.

ab+2a+b+2 ab+2a+b+2

The Extended Distributive Property

Detailed explanation

Practice Extended Distributive Property

Test your knowledge with 28 quizzes

Solve the following problem:

\( (x-8)(x+y)= \)

Examples with solutions for Extended Distributive Property

Step-by-step solutions included
Exercise #1

Resolve -

(xβˆ’3)(xβˆ’6)= (x-3)(x-6)=

Step-by-Step Solution

To solve this problem, we will expand the expression (xβˆ’3)(xβˆ’6)(x-3)(x-6) using the distributive property, which involves the following steps:

  • Step 1: Multiply the first terms of each binomial
    (x)(x)=x2(x)(x) = x^2

  • Step 2: Multiply the outer terms of the binomials
    (x)(βˆ’6)=βˆ’6x(x)(-6) = -6x

  • Step 3: Multiply the inner terms of the binomials
    (βˆ’3)(x)=βˆ’3x(-3)(x) = -3x

  • Step 4: Multiply the last terms of each binomial
    (βˆ’3)(βˆ’6)=18(-3)(-6) = 18

  • Step 5: Combine all the products
    x2βˆ’6xβˆ’3x+18x^2 - 6x - 3x + 18

  • Step 6: Combine like terms
    βˆ’6xβˆ’3x=βˆ’9x-6x - 3x = -9x, so we have
    x2βˆ’9x+18x^2 - 9x + 18

Therefore, the expanded form of (xβˆ’3)(xβˆ’6)(x-3)(x-6) is x2βˆ’9x+18\boxed{x^2 - 9x + 18}.

Therefore, the solution to the problem is x2βˆ’9x+18x^2 - 9x + 18. This corresponds to choice 1.

Answer:

x2βˆ’9x+18 x^2-9x+18

Video Solution
Exercise #2

Solve the exercise:

(2yβˆ’3)(yβˆ’4)= (2y-3)(y-4)=

Step-by-Step Solution

To solve the algebraic expression (2yβˆ’3)(yβˆ’4)(2y-3)(y-4), we will apply the distributive property, also known as the FOIL method for binomials. This involves multiplying each term in the first binomial by each term in the second binomial.

  • Step 1: Multiply the first terms: 2yΓ—y=2y2 2y \times y = 2y^2 .
  • Step 2: Multiply the outer terms: 2yΓ—βˆ’4=βˆ’8y 2y \times -4 = -8y .
  • Step 3: Multiply the inner terms: βˆ’3Γ—y=βˆ’3y -3 \times y = -3y .
  • Step 4: Multiply the last terms: βˆ’3Γ—βˆ’4=12 -3 \times -4 = 12 .

Next, we combine all these results: 2y2βˆ’8yβˆ’3y+12 2y^2 - 8y - 3y + 12 .

Then, we combine the like terms βˆ’8y-8y and βˆ’3y-3y to get βˆ’11y-11y.

Therefore, the expanded expression is 2y2βˆ’11y+12 2y^2 - 11y + 12 .

This matches choice (3): 2y2βˆ’11y+12 2y^2 - 11y + 12 .

Thus, the solution to the problem is 2y2βˆ’11y+12 2y^2 - 11y + 12 .

Answer:

2y2βˆ’11y+12 2y^2-11y+12

Video Solution
Exercise #3

Solve the exercise:

(3xβˆ’1)(x+2)= (3x-1)(x+2)=

Step-by-Step Solution

To solve this problem, we'll apply the distributive property to expand the expression (3xβˆ’1)(x+2)(3x-1)(x+2). Below are the steps:

  • Step 1: Distribute each term in the first binomial to each term in the second binomial:

3x(x)+3x(2)+(βˆ’1)(x)+(βˆ’1)(2)3x(x) + 3x(2) + (-1)(x) + (-1)(2)

  • Step 2: Calculate each term:

3x2+6xβˆ’xβˆ’23x^2 + 6x - x - 2

  • Step 3: Combine like terms:

3x2+(6xβˆ’x)βˆ’2=3x2+5xβˆ’23x^2 + (6x - x) - 2 = 3x^2 + 5x - 2

Thus, the expanded expression is 3x2+5xβˆ’23x^2 + 5x - 2.

The correct answer choice is 3x2+5xβˆ’23x^2 + 5x - 2, corresponding to choice id="4".

Answer:

3x2+5xβˆ’2 3x^2+5x-2

Video Solution
Exercise #4

Solve the exercise:

(5xβˆ’2)(3+x)= (5x-2)(3+x)=

Step-by-Step Solution

To solve the problem (5xβˆ’2)(3+x) (5x-2)(3+x) , we will use the distributive property, specifically the FOIL (First, Outer, Inner, Last) method, to expand the expression:

  • Step 1: Multiply the First terms: 5xΓ—3=15x 5x \times 3 = 15x .
  • Step 2: Multiply the Outer terms: 5xΓ—x=5x2 5x \times x = 5x^2 .
  • Step 3: Multiply the Inner terms: βˆ’2Γ—3=βˆ’6 -2 \times 3 = -6 .
  • Step 4: Multiply the Last terms: βˆ’2Γ—x=βˆ’2x -2 \times x = -2x .

Now combine all these products together:

5x2+15xβˆ’2xβˆ’6 5x^2 + 15x - 2x - 6

Combine the like terms 15x 15x and βˆ’2x -2x :

5x2+(15xβˆ’2x)βˆ’6=5x2+13xβˆ’6 5x^2 + (15x - 2x) - 6 = 5x^2 + 13x - 6

Thus, the expanded form of the expression is 5x2+13xβˆ’6 5x^2 + 13x - 6 .

Answer:

5x2+13xβˆ’6 5x^2+13x-6

Video Solution
Exercise #5

(3+20)Γ—(12+4)= (3+20)\times(12+4)=

Step-by-Step Solution

Simplify this expression paying attention to the order of arithmetic operations. Exponentiation precedes multiplication whilst division precedes addition and subtraction. Parentheses precede all of the above.

Therefore, let's first start by simplifying the expressions within the parentheses. Then we can proceed to perform the multiplication between them:

(3+20)β‹…(12+4)=23β‹…16=368 (3+20)\cdot(12+4)=\\ 23\cdot16=\\ 368

Therefore, the correct answer is option A.

Answer:

368

Video Solution

Frequently Asked Questions

What is the extended distributive property formula?

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The extended distributive property formula is (a+b)(c+d) = ac + ad + bc + bd. You multiply each term in the first parentheses by each term in the second parentheses, then combine like terms if possible.

How do you multiply two binomials step by step?

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Follow these steps: 1) Multiply the first term in the first binomial by each term in the second binomial, 2) Multiply the second term in the first binomial by each term in the second binomial, 3) Combine like terms to simplify your final answer.

What's the difference between basic and extended distributive property?

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Basic distributive property involves one term multiplied by a binomial: a(b+c) = ab + ac. Extended distributive property involves multiplying two binomials: (a+b)(c+d) = ac + ad + bc + bd.

How do you handle negative signs in extended distributive property?

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Treat negative signs as part of the terms. Remember that multiplying two negatives gives a positive result, while multiplying a positive and negative gives a negative result. For example: (-3)(-5) = +15, but (-3)(+5) = -15.

What are common mistakes when using extended distributive property?

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Common mistakes include: β€’ Forgetting to multiply all four combinations of terms β€’ Making sign errors with negative numbers β€’ Failing to combine like terms in the final answer β€’ Rushing through the multiplication without checking work

When do you use the extended distributive property in real life?

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The extended distributive property is used in calculating areas of rectangles with variable dimensions, solving quadratic equations, and simplifying algebraic expressions in physics and engineering problems.

Is FOIL the same as extended distributive property?

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Yes, FOIL (First, Outer, Inner, Last) is a memory device for the extended distributive property when multiplying two binomials. Both methods produce the same result by ensuring you multiply all combinations of terms.

How do you check if your extended distributive property answer is correct?

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You can check by: 1) Substituting simple numbers for variables and verifying both sides equal the same value, 2) Expanding your answer back to factored form, or 3) Using online algebra calculators to verify your work.

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