+945 55776
\( \begin{aligned} &945 \\ +& \\ &~~55 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
\( \begin{aligned} &957 \\ +& \\ &~~43 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
\( \begin{aligned} &987 \\ +& \\ &~~13 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
\( \begin{aligned} &921 \\ +& \\ &~~79 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
\( \begin{aligned} &977\\ +& \\ &~~23 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
To solve this vertical addition problem, we need to add 945 and 55. Let's work through this step-by-step, adding from right to left (from the ones place to the hundreds place).
Step 1: Set up the problem with proper alignment
We align the numbers by place value:
Step 2: Add the ones column
In the ones place, we have .
Since 10 equals 1 ten and 0 ones, we write 0 in the ones place and carry 1 to the tens column.
Step 3: Add the tens column
In the tens place, we have , plus the carried 1, giving us .
Since 10 equals 1 hundred and 0 tens, we write 0 in the tens place and carry 1 to the hundreds column.
Step 4: Add the hundreds column
In the hundreds place, we have (since 55 has no hundreds digit), plus the carried 1, giving us .
Since 10 equals 1 thousand and 0 hundreds, we write 0 in the hundreds place and carry 1 to the thousands column.
Step 5: Write the thousands digit
The carried 1 becomes our thousands digit.
The complete addition looks like this:
Therefore, the sum of 945 and 55 is .
1000
To solve this problem, we'll follow these steps:
We will align the numbers by their place values:
Add the digits in the ones place: .
Since 10 is greater than 9, write down 0 in the ones place and carry over 1 to the tens place.
Add the digits in the tens place, including the carry-over: .
Again, write down 0 in the tens place and carry over 1 to the hundreds place.
Add the digits in the hundreds place, including the carry-over: .
Write down the entire 10 since there is no further place to carry over.
The result of the addition is 1000.
Therefore, the solution to the problem is .
1000
To solve this problem, we'll perform a vertical addition of two numbers:
Add 7 (ones place of 987) to 3 (ones place of 13) to get 10. Since this sum is 10, we write down 0 in the ones place and carry over 1 to the tens place.
Add 8 (tens place of 987) to 1 (tens place of carry-over) + 1 (tens place of 13). This is 8 + 1 + 1 = 10. We write 0 in the tens place and carry over 1 to the hundreds place.
Add 9 (hundreds place of 987) to 1 (carry-over). This sum is 9 + 1 = 10. We write 0 in the hundreds place and carry over 1 to the next higher place, the thousands place.
Since the only carried-over is 1 to the thousands place, we write it as is. So the result of the addition is 1000.
Therefore, the solution to this problem is .
1000
To solve this problem, we'll follow these steps:
Let's work through the solution:
Step 1: We have the numbers aligned as:
Step 2: Start adding from the units column:
Step 3: Combine the results to obtain the final sum:
The sum is .
Therefore, the solution to the problem is .
1000
To solve this vertical addition problem, we follow these steps:
After completing all these steps, the final sum is .
1000