Vertical Addition Practice Problems - Step by Step Solutions

To solve this problem, we need to perform vertical addition of the numbers $83$ and $6$.

Let's work through the problem step-by-step:

• Write the numbers vertically, aligning them by place value:
       83
  +      6
  

  ---

• First, add the digits in the ones place:
      3 (from 83) + 6 = 9
• Next, add the digits in the tens place (given no carry was needed):
      8 (from 83) + 0 (implicit from 6) = 8
• Combine the results of those sums, which gives us the final result as:

$89$.

Therefore, the solution to the problem is $89$, which corresponds to the choice: :

89

We will perform vertical addition to find the sum of $92$ and $5$.

• Step 1: Align the numbers by place value:

$\begin{array}{c} 92 \\ +\,\,\,5 \\ \underline{\phantom{776}} \end{array}$

• Step 2: Add the rightmost column (units):

$2 + 5 = 7$. Write down $7$ under the units column.

• Step 3: Add the leftmost column (tens):

The tens digit of $92$ is $9$. As there are no tens in $5$, simply bring down $9$.

• Step 4: Combine:

Thus, writing the results from both columns, we have $97$.

Therefore, the sum of $92$ and $5$ is $97$.

To solve this addition problem, follow these steps:

• Step 1: Align the numbers vertically. We have the numbers $90$ and $9$.
• Step 2: Write them down with equal alignment such that their units digits are aligned:

$\begin{aligned} &90 \\ + &~9\\ \end{aligned}$

• Step 3: Begin by adding the rightmost column (units column): $0 + 9 = 9$. Write $9$ in the units place below the line.
• Step 4: Move to the left column (tens column). Add: $9 + 0 = 9$.
• Step 5: Write $9$ in the tens place below the line.

This gives us the complete sum:

$\begin{aligned} &90 \\ + &9 \\ \underline{~~~~} \\ &99 \\ \end{aligned}$

Therefore, the sum of $90$ and $9$ is $\textbf{99}$.

Referring to the multiple-choice answers provided, the correct choice is \textbf{choice 4: 99}.

To solve this problem, we will follow these steps:

• Step 1: Align the numbers vertically by place value. We have:
  $\begin{array}{c} 12 \\ + \\ \phantom{0}2 \\ \hline \end{array}$

• Step 2: Start from the rightmost digits in the units column. Add $2$ (from the bottom number) to $2$ (from the top number).
  $\phantom{x}2 + 2 = 4$

• Step 3: Now, move to the next column. We have $1$ in the tens column only from the top number, so it's $1 + 0 = 1$.

• Step 4: Combine the sums from each column starting from the left to form the final answer: $14$.

Therefore, the solution to the problem is $14$, which corresponds to choice 4.

To solve this problem, we'll add the numbers 24 and 4 using vertical addition:

• Step 1: Align the numbers vertically with the units and tens digits properly aligned:
$\begin{aligned} &24 \\ +& \\ &~~4 \\ \end{aligned}$

• Step 2: Add from the rightmost column (units position):
  The units digits are 4 and 4. Their sum is $4 + 4 = 8$.
• Step 3: Move to the next column (tens position):
  In this case, the tens digit of the first number is 2, and there is no tens digit in the number 4. Since there is no carry, we simply bring down the 2.

The sum of the numbers is 28, which is represented as:

$\begin{aligned} &28 \end{aligned}$

Therefore, the correct answer is 28, which corresponds to choice .