Vertical Addition Practice Problems - Step by Step Solutions

To solve this addition problem, follow these steps:

• Step 1: Align the numbers vertically. We have the numbers $90$ and $9$.
• Step 2: Write them down with equal alignment such that their units digits are aligned:

$\begin{aligned} &90 \\ + &~9\\ \end{aligned}$

• Step 3: Begin by adding the rightmost column (units column): $0 + 9 = 9$. Write $9$ in the units place below the line.
• Step 4: Move to the left column (tens column). Add: $9 + 0 = 9$.
• Step 5: Write $9$ in the tens place below the line.

This gives us the complete sum:

$\begin{aligned} &90 \\ + &9 \\ \underline{~~~~} \\ &99 \\ \end{aligned}$

Therefore, the sum of $90$ and $9$ is $\textbf{99}$.

Referring to the multiple-choice answers provided, the correct choice is \textbf{choice 4: 99}.

To solve this problem, we will follow these steps:

• Step 1: Align the numbers vertically by place value. We have:
  $\begin{array}{c} 12 \\ + \\ \phantom{0}2 \\ \hline \end{array}$

• Step 2: Start from the rightmost digits in the units column. Add $2$ (from the bottom number) to $2$ (from the top number).
  $\phantom{x}2 + 2 = 4$

• Step 3: Now, move to the next column. We have $1$ in the tens column only from the top number, so it's $1 + 0 = 1$.

• Step 4: Combine the sums from each column starting from the left to form the final answer: $14$.

Therefore, the solution to the problem is $14$, which corresponds to choice 4.

To solve this problem, we will follow these steps:

• Step 1: Align the numbers vertically with the units digits under each other: $31$ and $6$.
• Step 2: Add the units digits: $1 + 6 = 7$. There is no carryover in this simple addition.
• Step 3: The tens digit from the number 31, which is $3$, remains unchanged as there is no carry that affects this place value.
• Step 4: Write down the result of the addition, which is $37$.

Therefore, the sum of $31$ and $6$ is $37$.

The correct answer is choice 1: $37$.

To solve this problem, we'll perform vertical addition of the numbers 40 and 3:

• Step 1: Write the numbers vertically, aligning by place value:
  $\begin{array}{c} 40 \\ + 3 \\ \hline \end{array}$
• Step 2: Start adding from the rightmost column (units place).
  Units column: 0 + 3 = 3, write this number directly below the line.
  $\begin{array}{c} 40 \\ + 3 \\ \hline 43 \\ \end{array}$
• Step 3: Move to the next column (tens place):
  In the tens place: 4 + 0 = 4, write this number below the line in the tens place.

As a final result, the sum of 40 and 3 is 43.

Therefore, the solution to the problem is $43$, which matches choice number 4 in the provided options.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers $44$ and $4$ such that digits of the same place value (units) are below one another.
• Step 2: Add the digits in the units column. This means summing $4$ and $4$ to get $8$.
• Step 3: Check for carry over, if any, and add digits in the next column (tens column). In this case, there's no carry over needed, so just add the digit $4$ from $44$ with the implied $0$ from $4$ (tens place) to get $4$.
• Step 4: Combine the results. The tens place gives $4$ and the units place gives $8$, forming the number $48$.

Now, let's work through each step:
Step 1: Vertical alignment:
$\begin{array}{c} 44 \\ + 04 \\ \hline \end{array}$
Step 2: Units column $4 + 4 = 8$ (no carry over).
Step 3: Tens column $4 + 0 = 4$.
Step 4: Combining the tens and units results: the number is $48$.

Therefore, the sum of $44$ and $4$ is $48$. The correct choice from the provided options is choice $3$.