Examples with solutions for Surface Area of a Cuboid: Using ratios for calculation

Exercise #1

The ratio of the length of the height in the cuboid to the length of the width 3:5.

Height of the cuboid whose ratio is 2:7 long.

Given that the area of the cuboid 542 cm². Find its dimensions.

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Express dimensions in terms of a single variable using the given ratios.

  • Step 2: Substitute these expressions into the cuboid's surface area formula.

  • Step 3: Solve for the variable and in turn calculate the dimensions.

Now, let's work through each step:

Step 1: Express dimensions using the ratios.
- Let h=3xh = 3x (height is set from height to width ratio), w=5xw = 5x (width), l=72h=72(3x)=212xl = \frac{7}{2}h = \frac{7}{2}(3x) = \frac{21}{2}x (length from 2:7 as basis relative to height).

Step 2: Substitute into the surface area formula.
The surface area SS is given by:
S=2(lw+lh+wh)=542cm2 S = 2(lw + lh + wh) = 542 \, \text{cm}^2

Plugging in, we get:
2(212x5x+212x3x+3x5x)=542 2\left(\frac{21}{2}x \cdot 5x + \frac{21}{2}x \cdot 3x + 3x \cdot 5x\right) = 542

Simplifying further:
2(1052x2+632x2+15x2)=542 2\left(\frac{105}{2}x^2 + \frac{63}{2}x^2 + 15x^2\right) = 542

Combining terms, we get:
2×(105x2+63x2+30x22)=542 2 \times \left(\frac{105x^2 + 63x^2 + 30x^2}{2}\right) = 542

The combined denominator cancels out:
198x2=542 198x^2 = 542

Solving for x2x^2:
x2=5421982.737 x^2 = \frac{542}{198} \approx 2.737

Solving for xx:
x2.7371.654 x \approx \sqrt{2.737} \approx 1.654

Step 3: Calculate dimensions using xx:
- h=3x3×1.6544.96cm h = 3x \approx 3 \times 1.654 \approx 4.96 \, \text{cm}
- w=5x5×1.6548.26cm w = 5x \approx 5 \times 1.654 \approx 8.26 \, \text{cm}
- l=212x212×1.65417.36cm l = \frac{21}{2}x \approx \frac{21}{2} \times 1.654 \approx 17.36 \, \text{cm}

Therefore, the solution to the problem is Height =4.96cm, Length =17.36cm, Width =8.26cm \text{Height } = 4.96 \, \text{cm}, \text{ Length } = 17.36 \, \text{cm}, \text{ Width } = 8.26 \, \text{cm} , which matches choice 4.

Answer

Height 4.96, Length 8.26, Width 17.36

Exercise #2

The ratio between the height and the width of the cuboid 3:5.

The length of the cuboid l and greater than 3 of the height.

Express using l the surface area of the cuboid.

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Video Solution

Step-by-Step Solution

To solve this problem, we'll express the dimensions of the cuboid in terms of the length l l .

  • The given ratio of height to width is 3:5, which means h=35w h = \frac{3}{5}w .
  • We are told that the length l l is greater than 3 times the height. Therefore, l=3h+k l = 3h + k for some k>0 k > 0 .

For simplicity, if we assume l=3h l = 3h , then substituting h=35w h = \frac{3}{5}w gives l=3×35w=95w l = 3 \times \frac{3}{5}w = \frac{9}{5}w .

To express w w in terms of l l , we solve w=59l w = \frac{5}{9}l .

Now, express the height h h in terms of l l using the relationship h=35×59l=13l h = \frac{3}{5} \times \frac{5}{9}l = \frac{1}{3}l .

These substitutions allow us to express all dimensions in terms of l l :
Width, w=59l w = \frac{5}{9}l
Height, h=13l h = \frac{1}{3}l

The surface area A A of the cuboid is given by:

A=2(lw+lh+wh) A = 2(lw + lh + wh)

Substitute the expressions for w w and h h :

A=2(l×59l+l×13l+59l×13l) A = 2\left(l \times \frac{5}{9}l + l \times \frac{1}{3}l + \frac{5}{9}l \times \frac{1}{3}l\right)

A=2(59l2+13l2+527l2) A = 2\left(\frac{5}{9}l^2 + \frac{1}{3}l^2 + \frac{5}{27}l^2\right)

Simplify the expression inside the parentheses:

A=2(1527l2+927l2+527l2) A = 2\left(\frac{15}{27}l^2 + \frac{9}{27}l^2 + \frac{5}{27}l^2\right)

A=2(2927l2) A = 2\left(\frac{29}{27}l^2\right)

A=5827l2 A = \frac{58}{27}l^2

Therefore, the expression for the surface area in terms of l l is 5827l2\frac{58}{27}l^2. This matches the given answer.

Answer

5827l2 \frac{58}{27}l^2

Exercise #3

A cuboid exists with a ratio between its dimensions equaling 1:2:4. The middle side has a length of 5 cm.

What is the surface area of the cuboid?

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Solve for the variable x x using the given ratio and dimension.
  • Step 2: Calculate the dimensions of the cuboid.
  • Step 3: Apply the surface area formula for a cuboid.
  • Step 4: Carry out the calculations to find the total surface area.

Now, let's work through each step:

Step 1: Solving for x x

We know that the dimensions of the cuboid are in the ratio 1:2:4 1:2:4 . Assigning the dimensions as x x , 2x 2x , and 4x 4x , and knowing that the middle dimension is 5 cm, we have 2x=5 2x = 5 . Solving for x x , we get:

x=52=2.5 cm x = \frac{5}{2} = 2.5 \text{ cm}

Step 2: Calculate the dimensions

Now, using the value of x x :

  • First dimension: x=2.5 cm x = 2.5 \text{ cm}
  • Second dimension: 2x=5 cm 2x = 5 \text{ cm}
  • Third dimension: 4x=10 cm 4x = 10 \text{ cm}

Step 3: Apply the surface area formula

The formula for the surface area of a cuboid is:

A=2(lw+lh+wh) A = 2(lw + lh + wh)

Substitute the dimensions into the formula:

A=2(2.5×5+2.5×10+5×10) A = 2(2.5 \times 5 + 2.5 \times 10 + 5 \times 10)

Step 4: Perform the calculations

Calculate each term:

2.5×5=12.5 2.5 \times 5 = 12.5

2.5×10=25 2.5 \times 10 = 25

5×10=50 5 \times 10 = 50

Now, calculate the total inside the parenthesis:

A=2(12.5+25+50)=2(87.5) A = 2(12.5 + 25 + 50) = 2(87.5)

A=175 cm2 A = 175 \text{ cm}^2

Therefore, the surface area of the cuboid is 175 cm2\mathbf{175 \text{ cm}^2}.

Answer

175 cm².

Exercise #4

A rectangular prism is shown below.

The ratio between b and a is 3:4, while the ratio between b and c is 7:9.

a = 6 cm

Calculate the surface area of the rectangular prism.

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Video Solution

Answer

175.8 cm²