Examples with solutions for Perimeter of a Rectangle: Using congruence and similarity

Exercise #1

ΔBCD∼ΔFED

Calculate the perimeter of the rectangle EFGD.

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Video Solution

Step-by-Step Solution

To solve for the perimeter of rectangle EFGD EFGD , we follow these steps:

Step 1: Use the similarity of the triangles BCDFED \triangle BCD \sim \triangle FED . This implies the sides are proportional:

CDED=BCEF \frac{CD}{ED} = \frac{BC}{EF}

Substitute the known lengths CD=8 CD = 8 and ED=3 ED = 3 :

83=6EF \frac{8}{3} = \frac{6}{EF}

Solving for EF EF , cross-multiply:

8×EF=3×6 8 \times EF = 3 \times 6 EF=188=2.25 EF = \frac{18}{8} = 2.25

Step 2: The length and width of rectangle EFGD EFGD are 2.25 2.25 (as calculated from EF EF ) and 3 3 (equal to ED ED ).

Step 3: Calculate the perimeter P P of EFGD EFGD :

P=2×(EF+ED)=2×(2.25+3)=2×5.25 P = 2 \times (EF + ED) = 2 \times (2.25 + 3) = 2 \times 5.25 P=10.5 P = 10.5

The perimeter of rectangle EFGD EFGD is 10.5 10.5 .

Answer

10.5

Exercise #2

ΔAED≅ΔBCD

Calculate the perimeter of the rectangle AFDE.

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Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Analyze the congruent triangles.

  • Step 2: Use congruence to identify side lengths.

  • Step 3: Calculate the perimeter of the rectangle.

Now, let's work through each step:
Step 1: The problem states that AEDBCD\triangle AED \cong \triangle BCD, which means corresponding sides and angles are equal.
Step 2: Identify corresponding sides from congruence:
- AE=CD=6AE = CD = 6 because corresponding sides of congruent triangles are equal.
- AD=BCAD = BC. Since AB=8AB = 8 and using the fact AED\triangle AED and BCD\triangle BCD are congruent, BDBD (the same as ADAD) must also equal 6 (from the congruence starting from point DD).
- Thus, AD=6AD = 6.

Step 3: Calculate the perimeter: AF=DE=6AF = DE = 6 from congruency and AD=FE=6AD = FE = 6. Since both pairs of opposite sides of the rectangle are equal, the rectangle perimeter is:
P=2(AF+AD)=2(6+8)=2×14=28 P = 2(AF + AD) = 2(6 + 8) = 2 \times 14 = 28

Therefore, the perimeter of the rectangle AFDEAFDE is 2828.

Answer

28

Exercise #3

ΔBCE≅ΔFED

Calculate the perimeter of the rectangle EDGF.

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Video Solution

Step-by-Step Solution

To find the perimeter of rectangle EDGF, we will follow these steps:

  • Step 1: Recognize congruence ΔBCEΔFED\Delta BCE \equiv \Delta FED.
  • Step 2: Use congruent triangles to find side lengths of ED and DF.
  • Step 3: Calculate the perimeter using the formula for rectangles.

Now, let's proceed with the solution:

Step 1: Given ΔBCE\Delta BCE and ΔFED\Delta FED are congruent triangles, their corresponding sides are equal. Thus, since BC=6BC = 6, it follows that ED=BC=6ED = BC = 6.

Step 2: From the configuration of the rectangle, note that FEFE (same as AE) is given to be 8, hence GF=8GF = 8 because EDGF is a rectangle.

Step 3: The perimeter of rectangle EDGF can be calculated using:

P=2×(Length+Width)=2×(ED+DF)=2×(6+8)=28 P = 2 \times (\text{Length} + \text{Width}) = 2 \times (ED + DF) = 2 \times (6 + 8) = 28

Therefore, the solution to the problem is that the perimeter of rectangle EDGF is 28.

Answer

28

Exercise #4

ΔBCD∼ΔECF

Calculate the perimeter of the rectangle ABCD.

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Video Solution

Answer

28

Exercise #5

ΔBDC∼ΔBDE

Calculate the perimeter of the rectangle ABDE.

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Video Solution

Answer

14

Exercise #6

ΔBCD∼ΔDFG

Calculate the perimeter of the rectangle EDFG.

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Video Solution

Answer

26213 26\frac{2}{13}

Exercise #7

ΔADC∼ΔBCE

Calculate the perimeter of the rectangle EBCF.

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Video Solution

Answer

8

Exercise #8

ΔADC∼ΔBCE

Calculate the perimeter of the rectangle ABCD.

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Video Solution

Answer

14

Exercise #9

ΔAED≅ΔBCD

What is the perimeter of the rectangle ABCD?

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Video Solution

Answer

40

Exercise #10

ΔBCE≅ΔFED

Calculate the perimeter of the rectangle ABCE.

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Video Solution

Answer

28