Perimeter of a Triangle - Examples, Exercises and Solutions

Given that in a rectangle every pair of opposite sides are equal to each other, we can state that:

$AB=CD=2$

$AD=BC=7$

Now we can add all the sides together and find the perimeter:

$2+7+2+7=4+14=18$

In the drawing, we have a rectangle, although it is not placed in its standard form and is slightly rotated,
but this does not affect that it is a rectangle, and it still has all the properties of a rectangle.
 
The perimeter of a rectangle is the sum of all its sides, that is, to find the perimeter of the rectangle we will have to add the lengths of all the sides.
We also know that in a rectangle the opposite sides are equal.
Therefore, we can use the existing sides to complete the missing lengths.
 
4.8+4.8+12+12 =
33.6 cm

Since in a rectangle every pair of opposite sides are equal to each other, we can state that:

$AD=BC=9.5$

$AB=CD=1.5$

Now we can add all the sides together and find the perimeter:

$1.5+9.5+1.5+9.5=19+3=22$

The perimeter of the triangle is equal to the sum of all sides together, therefore:

$6+8+10=14+10=24$

The perimeter of a triangle is equal to the sum of all its sides together:

$11+7+13=11+20=31$

In order to calculate the perimeter of the trapezoid we must add together the measurements of all of its sides:

7+10+7+12 =

36

And that's the solution!

The problem requires calculating the perimeter of the trapezoid by summing the lengths of its sides. Based on the given trapezoid diagram, the side lengths are clearly marked as follows:

• First side: $4$
• Second side: $9$
• Third side: $6$
• Fourth side: $13$

According to the formula for the perimeter of a trapezoid:

$P = a + b + c + d$

Substituting the respective values:

$P = 4 + 9 + 6 + 13$

Calculating the sum, we find:

$P = 32$

Thus, the perimeter of the trapezoid is $32$.

To find the perimeter we will add all the sides:

$4+5+9+6=9+9+6=18+6=24$

To find the perimeter of the trapezoid, we will sum the lengths of all its sides. The given side lengths are:

• Base 1: $7.5$
• Base 2: $1.5$
• Leg 1: $3$
• Leg 2: $4$

Using the formula for the perimeter $P$ of the trapezoid, we have:

$P = a + b + c + d$

Substituting in the given values:

$P = 7.5 + 1.5 + 3 + 4$

Performing the addition:

$P = 7.5 + 1.5 = 9$

$P = 9 + 3 = 12$

$P = 12 + 4 = 16$

Therefore, the perimeter of the trapezoid is $16$.

To solve this problem, we'll follow these steps:

• Step 1: Identify all given side lengths of the trapezoid.
• Step 2: Apply the formula for the perimeter of the trapezoid.
• Step 3: Sum up the lengths to find the perimeter.

Now, let's work through each step:
Step 1: The problem gives us the lengths of the trapezoid's sides:
- $AB = 2.5$
- $BC = 10.4$
- $CD = 5.3$
- $DA = 6$

Step 2: We use the formula for the perimeter of a trapezoid:

$P = AB + BC + CD + DA$

Step 3: Plugging in the given values, we calculate:

$P = 2.5 + 10.4 + 5.3 + 6$

Calculating further, we have:

$P = 24.2$

Therefore, the perimeter of the trapezoid is $24.2$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the given measurements for the sides.

• Step 2: Use the perimeter formula for a trapezoid, which is summing all sides.

• Step 3: Add the values to get the perimeter.

Now, let's work through each step:

Step 1: The problem gives us four sides to consider. These sides are: $AB = 5$, $CD = 7$, $AC = 4$, and $BD = 4$.

Step 2: The perimeter of a trapezoid or any quadrilateral is simply the sum of all four sides. Hence, we need to add $AB$, $CD$, $AC$, and $BD$.

Step 3: Adding the values, we calculate the perimeter:$AB + CD + AC + BD = 5 + 7 + 4 + 4 = 20$.

Therefore, the perimeter of the given shape is $20$.

To solve this problem, we'll follow these steps:

• Step 1: Gather the given side lengths of quadrilateral ABCD.

• Step 2: Since it's necessary to understand summation, add all lengths.

• Step 3: Conclude from sum.

Now, let's work through each step:

Step 1: The problem provides:
$\begin{aligned} AB &= 10.5, \\ CD &= 13, \\ AC &= 7.5, \\ BD &= 7.5. \end{aligned}$

Step 2: Add them together:
$\begin{aligned} \text{Perimeter} &= AB + CD + AC + BD \\ &= 10.5 + 13 + 7.5 + 7.5. \end{aligned}$

Step 3: Calculate: $\begin{aligned} \text{Perimeter} &= 10.5 + 13 + 7.5 + 7.5 = 38.5. \end{aligned}$

Therefore, the solution is that the perimeter of quadrilateral ABCD is $38.5$ .

As is true for a parallelogram every pair of opposite sides are equal:

$AB=CD=6,AC=BD=4$

The perimeter of the parallelogram is equal to the sum of all sides together:

$4+4+6+6=8+12=20$

To solve this problem, let's follow these steps:

• Step 1: Identify the lengths of the adjacent sides of the parallelogram.
• Step 2: Use the formula for the perimeter of a parallelogram, $P = 2(a + b)$.
• Step 3: Plug in the known values and calculate the perimeter.

Now, let's work through each step:

Step 1: From the diagram, we have two adjacent sides of the parallelogram: $a = 8$ units and $b = 3$ units.

Step 2: The formula for the perimeter of a parallelogram is given by $P = 2(a + b)$.

Step 3: Substitute the values for $a$ and $b$ into the formula:

$P = 2(8 + 3) = 2 \times 11 = 22$.

Therefore, the perimeter of the parallelogram is $22$.

To solve the problem of calculating the perimeter of the parallelogram, follow these steps:

• Identify the given side lengths: $AB = 5$ and $AC = 4$.
• Acknowledge that in a parallelogram, opposite sides are equal, so $AB = CD = 5$ and $AC = BD = 4$.
• Apply the perimeter formula for a parallelogram: $P = 2 \times ( \text{Base} + \text{Side} )$.

Plug the known side lengths into the formula:
$P = 2 \times (AB + AC) = 2 \times (5 + 4) = 2 \times 9 = 18$

Thus, the perimeter of the parallelogram is $18$.