A projectile is fired at a speed of 2500 km/h and travels 135 meters until it hits its target.
It passes through the target, which reduces its speed to 1300 km/h, after which point it continues for another 1.8 seconds until it hits a wall.
What is its average speed from the moment of firing until it stops?
Step 1: Convert speeds from km/h to m/s.
- Initial speed: 2500 km/h=36002500×1000 m/s=36002500000≈694.44 m/s
- Speed after hitting the target: 1300 km/h=36001300×1000 m/s=36001300000≈361.11 m/s
Step 2: Calculate the time to reach the target.
Using the formula time=speeddistance:
Time to target: 694.44 m/s135 m≈0.1944 seconds
Step 3: Calculate the total distance.
Total distance traveled = 135 meters (to the target) + distance traveled after the target.
Distance after target: 361.11 m/s×1.8 seconds=649.998 meters≈650 meters
Total distance = 135+650=785 meters
Step 4: Calculate the total time.
Total time = time to target + time after target = 0.1944 seconds+1.8 seconds=1.9944 seconds
Step 5: Calculate the average speed.
Using Average speed=Total timeTotal distance:
Average speed = 1.9944 s785 m≈393.68 m/s
Upon reviewing the final average speed calculation, we note that the earlier provided correct answer of 248.75 meters per second does not align with this result, indicating discrepancies in either calculation or initial assumptions. Nevertheless, the calculated solution above is 393.68 meters per second.
393.68 meters per second