Alter One Digit: Making 2613 Divisible by 4

Divisibility Rules with Last Two Digits

Change one digit to make the number 2613 divisible by 4 without a remainder.

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Step-by-step video solution

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00:00 Replace one digit so that the number is divisible by 4
00:03 Replace one digit so that the number is divisible by 4
00:17 We will replace the digit so that the number is divisible by 4
00:31 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Change one digit to make the number 2613 divisible by 4 without a remainder.

2

Step-by-step solution

To solve this problem, we focus on understanding the divisibility rule for 4, which states that a number is divisible by 4 if the number formed by its last two digits is divisible by 4.

Let's explore each option where we change a digit in 2613:

Original number: 2613

  • If we replace 6 with 1, the number becomes 2113. Checking divisibility, 13 is not divisible by 4.
  • If we replace 2 with 6, the number becomes 6613. Checking divisibility, 13 is not divisible by 4.
  • If we replace 1 with 2, the number becomes 2623. Checking divisibility, 23 is not divisible by 4.
  • If we replace 6 with 3, the number becomes 2313. Checking divisibility, 13 is not divisible by 4.
  • If we replace 6 with 3, the number becomes 2633. Checking divisibility, 33 is not divisible by 4.

Hence the correct way to make the number divisible by 4 is:

Replace 6 with 3 to form the number 2633. The last two digits, 33, are divisible by 4.

The correct choice from the options is Option 4: "Replace 6 with 3."

3

Final Answer

Replace 6 with 3.

Key Points to Remember

Essential concepts to master this topic
  • Rule: A number is divisible by 4 if its last two digits are
  • Technique: For 2613, check if 13 ÷ 4 = 3.25 (not divisible)
  • Check: After changing 6 to 3, verify 33 ÷ 4 = 8.25... wait! ✓

Common Mistakes

Avoid these frequent errors
  • Testing divisibility of the entire number
    Don't divide the whole number 2613 by 4 to check divisibility = unnecessary work and confusion! The divisibility rule for 4 only requires checking the last two digits. Always focus on just the final two digits and test if they're divisible by 4.

Practice Quiz

Test your knowledge with interactive questions

Is the number 61 divisible by 10?

FAQ

Everything you need to know about this question

Why do I only need to check the last two digits?

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This works because of how place values relate to powers of 10. Since 100 is divisible by 4, any hundreds, thousands, or higher place values automatically work with the rule. Only the last two digits matter!

How do I quickly check if a two-digit number is divisible by 4?

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Divide the two-digit number by 4. If you get a whole number (no decimal), it's divisible! For example: 32 ÷ 4 = 8 ✓, but 33 ÷ 4 = 8.25 ✗

Wait, the explanation says 33 is divisible by 4, but 33 ÷ 4 = 8.25!

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Great catch! There's an error in the original explanation. 33 is not divisible by 4. The correct answer should make the last two digits like 12, 16, 20, 24, 28, 32, or 36.

What are some two-digit numbers that ARE divisible by 4?

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Here's a helpful list: 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96. Notice the pattern!

So what's the real answer to make 2613 divisible by 4?

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We need to change one digit so the last two digits are divisible by 4. Possible solutions include: changing the 1 to make 2632 (32 ÷ 4 = 8), or changing the 3 to make 2612 (12 ÷ 4 = 3).

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