Change one digit to make the number 2613 divisible by 4 without a remainder.
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Change one digit to make the number 2613 divisible by 4 without a remainder.
To solve this problem, we focus on understanding the divisibility rule for 4, which states that a number is divisible by 4 if the number formed by its last two digits is divisible by 4.
Let's explore each option where we change a digit in 2613:
Original number: 2613
Hence the correct way to make the number divisible by 4 is:
Replace 6 with 3 to form the number 2633. The last two digits, 33, are divisible by 4.
The correct choice from the options is Option 4: "Replace 6 with 3."
Replace 6 with 3.
Is the number 61 divisible by 10?
This works because of how place values relate to powers of 10. Since 100 is divisible by 4, any hundreds, thousands, or higher place values automatically work with the rule. Only the last two digits matter!
Divide the two-digit number by 4. If you get a whole number (no decimal), it's divisible! For example: 32 ÷ 4 = 8 ✓, but 33 ÷ 4 = 8.25 ✗
Great catch! There's an error in the original explanation. 33 is not divisible by 4. The correct answer should make the last two digits like 12, 16, 20, 24, 28, 32, or 36.
Here's a helpful list: 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96. Notice the pattern!
We need to change one digit so the last two digits are divisible by 4. Possible solutions include: changing the 1 to make 2632 (32 ÷ 4 = 8), or changing the 3 to make 2612 (12 ÷ 4 = 3).
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