Change one digit to make the number 2315 divisible by 2 without a remainder.
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Change one digit to make the number 2315 divisible by 2 without a remainder.
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: We have the number 2315.
Step 2: The last digit is 5, which is an odd number, so 2315 is not divisible by 2.
Step 3: To make the number divisible by 2, replace the last digit 5 with 4, an even number.
This gives us the number 2314. As 4 is an even number, 2314 is divisible by 2.
Therefore, the correct solution is to replace the last digit with , resulting in a number, 2314, that is divisible by 2.
Thus, the solution to the problem is to replace 5 with 4 to make the number 2314.
Replace 2 with 5
Is the number 43 divisible by 4?
The divisibility rule for 2 depends only on the units place! If the last digit is even (0, 2, 4, 6, 8), the entire number is divisible by 2, regardless of other digits.
Yes! You can use 0, 2, 4, 6, or 8 to replace the 5. All of these will make 2315 divisible by 2. The problem asks to change one digit, so any even replacement works.
This seems like an error in the answer choices! Replacing 2 with 5 gives us 5315, which still ends in 5 (odd) and is not divisible by 2. The correct answer should involve changing the last digit 5.
Simply look at the last digit! If it's 0, 2, 4, 6, or 8, the number is divisible by 2. You can also divide by 2 on a calculator - if there's no decimal remainder, it's divisible.
Each number has its own divisibility rule! For example, divisibility by 3 depends on the sum of all digits, while divisibility by 5 requires the last digit to be 0 or 5.
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